Unto
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This is just my own practise question.
I have a relationship of
r = \frac{D}{2}sin4\theta
The apparent error formula is now:
\left(\frac{\Lambda r}{r}\right)^{2} = \left(\frac{\Lambda D}{D}\right)^{2} + 16 \left(\frac{\Lambda \theta}{tan 4 \theta}\right)^{2}
Using a standard combination of errors formula, I only get
\left(\frac{\Lambda r}{r}\right)^{2} = \left(\frac{\Lambda D}{D}\right)^{2} + 16 \left(\frac{\Lambda \theta}{4 \theta}\right)^{2}
Since I know there would be an error in the measurement of the angle. The 16 I'm also unsure of anyway, I just guessed you had to square the 4 and put it on the outside. How to you do errors for trigonometric identities is what I want to know. How do you go from sin to tan and what is the reasoning behind what they did and came out with?
Here is the error formula I think I am supposed to use
\left(\frac{\Lambda F }{F}\right)^{2} = k^{2} \left(\frac{\Lambda A}{A}\right)^{2} + l^{2} \left(\frac{\Lambda B}{B}\right)^{2}
Thank you for any help
I have a relationship of
r = \frac{D}{2}sin4\theta
The apparent error formula is now:
\left(\frac{\Lambda r}{r}\right)^{2} = \left(\frac{\Lambda D}{D}\right)^{2} + 16 \left(\frac{\Lambda \theta}{tan 4 \theta}\right)^{2}
Using a standard combination of errors formula, I only get
\left(\frac{\Lambda r}{r}\right)^{2} = \left(\frac{\Lambda D}{D}\right)^{2} + 16 \left(\frac{\Lambda \theta}{4 \theta}\right)^{2}
Since I know there would be an error in the measurement of the angle. The 16 I'm also unsure of anyway, I just guessed you had to square the 4 and put it on the outside. How to you do errors for trigonometric identities is what I want to know. How do you go from sin to tan and what is the reasoning behind what they did and came out with?
Here is the error formula I think I am supposed to use
\left(\frac{\Lambda F }{F}\right)^{2} = k^{2} \left(\frac{\Lambda A}{A}\right)^{2} + l^{2} \left(\frac{\Lambda B}{B}\right)^{2}
Thank you for any help