Combining functions and Domain

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The discussion focuses on finding the composition of functions F(x) = √x and G(x) = 2/(x-4), specifically g(f(x)) and its domain. The user initially struggles with determining the correct domain, mistakenly believing it includes x ≠ 16. Clarification reveals that the domain should consider where g(f(x)) is undefined, which occurs when f(x) = 4, leading to x = 16. The correct domain is thus x > 0 and x ≠ 4, as x = 4 does not affect the domain of g(f(x)). The conversation emphasizes the importance of understanding how the domains of both functions interact in compositions.
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Homework Statement



F(x)=√x

G(x)= 2/(x-4)

Find g(f(x)) and its domain

Homework Equations


The Attempt at a Solution



I am having trouble finding the domain for this composition. I know that g(f(x))= 2/(√x)-4

I believe that for the domain you combine the domain of the input (f(x)) and the output (g(f(x)). This would then be x > 0 (for f(x)) and x≠16 in g(f(x)). The answer key that I have says that the answer is x>0, x≠4

Where am I going wrong? Why does it disregard 16?

Thanks!
 
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ThomasMagnus said:

Homework Statement



F(x)=√x

G(x)= 2/(x-4)

Find g(f(x)) and it's domain

Homework Equations


The Attempt at a Solution



I am having trouble finding the domain for this composition. I know that g(f(x))= 2/(√x)-4

I believe that for the domain you combine the domain of the input (f(x)) and the output (g(f(x)). This would then be x > 0 (for f(x)) and x≠16 in g(f(x)). The answer key that I have says that the answer is x>0, x≠4

Where am I going wrong? Why does it disregard 16?

Thanks!

You aren't going wrong. The answer key is wrong. Though x could be zero, right?
 
Dick said:
You aren't going wrong. The answer key is wrong. Though x could be zero, right?

Woops, I should have put x≥0.

So for these types of problems, the domain of the combined function will be the domain of the input and the composed function? Why is the other ignored? i.e why can x be 4 if it will make g divide by 0?
 
ThomasMagnus said:
Woops, I should have put x≥0.

So for these types of problems, the domain of the combined function will be the domain of the input and the composed function? Why is the other ignored? i.e why can x be 4 if it will make g divide by 0?

You didn't ignore the 4. That's why you said 16 isn't in the domain, right? Yes, it's the domain of g(f(x)) you want.
 
Dick said:
You didn't ignore the 4. That's why you said 16 isn't in the domain, right? Yes, it's the domain of g(f(x)) you want.

But why can x be 4 if it makes g(x) undefined?. Don't I have to also say x≠4?
 
ThomasMagnus said:
But why can x be 4 if it makes g(x) undefined?. Don't I have to also say x≠4?
You're working with g(f(x)).

Therefore, if g(4) is undefined, then g(f(x)) is undefined when f(x) = 4.

For what value of x is f(x) = 4 ?
 
ThomasMagnus said:
But why can x be 4 if it makes g(x) undefined?. Don't I have to also say x≠4?

g(f(4))=g(2)=(-1). It's not undefined at all when x=4. It's undefined at x=16, when f(16)=4 and g(4) is undefined. Or it's undefined when x<0 when f(x) is undefined. As you said to begin with.
 
SammyS said:
You're working with g(f(x)).

Therefore, if g(4) is undefined, then g(f(x)) is undefined when f(x) = 4.

For what value of x is f(x) = 4 ?

Aha 16. So, with compositions of functions you're paying attention to the input (in this case f(x)) and the final compositions (g(f(x)). So the domain of the whole thing is pretty much the input and composed function domains combined?

Thanks for all the help! :)
 

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