Calculating Commutator of Position and Momentum: Troubleshooting Tips

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Discussion Overview

The discussion focuses on the calculation of the commutator [\hat{X}^2,\hat{P}^2], where \hat{X} represents position and \hat{P} represents momentum. Participants explore the implications of the calculation, particularly concerning the anti-Hermitian property of commutators involving Hermitian operators.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a calculation of the commutator [\hat{X}^2,\hat{P}^2] and expresses confusion about the result being non-anti-Hermitian.
  • Another participant suggests that the issue may arise from not swapping \hat{P} and \hat{X} when checking anti-Hermicity.
  • Further, a participant questions whether the term 2\hbar^2 affects the anti-Hermicity of the overall expression.
  • Another participant provides a rule for calculating commutators involving squares of operators, which may help clarify the situation.
  • A later reply acknowledges a mistake in forgetting to change the order of \hat{X} and \hat{P} during the calculation.

Areas of Agreement / Disagreement

Participants express differing views on the implications of the calculated terms regarding anti-Hermicity, and there is no consensus on the correct approach to resolving the issue.

Contextual Notes

Participants discuss the properties of Hermitian operators and the implications of their commutators, but the discussion does not resolve the mathematical steps or assumptions involved in the calculation.

antibrane
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I am attempting to calculate the commutator [\hat{X}^2,\hat{P}^2] where \hat{X} is position and \hat{P} is momentum and am running into the following problem. The calculation goes as follows,

<br /> [\hat{X}^2,\hat{P}^2]=-\left(\underbrace{[\hat{P}^2,\hat{X}]}_{-2i\hbar\hat{P}}\hat{X}+\hat{X}\underbrace{[\hat{P}^2,\hat{X}]}_{-2i\hbar\hat{P}}\right)=2i\hbar\left(\hat{P}\hat{X}+\hat{X}\hat{P}\right)<br />

and using that [\hat{X},\hat{P}]=i\hbar we find that

<br /> [\hat{X}^2,\hat{P}^2]=2i\hbar\left[\left(\hat{X}\hat{P}-i\hbar\right)+\hat{X}\hat{P}\right]=4i\hbar\hat{X}\hat{P}+2\hbar^2<br />

which is wrong because I know from a theorem that if \hat{A} is Hermitian and \hat{B} is Hermitian then [\hat{A},\hat{B}] is anti-Hermitian, which is definitely not the case here. What am I doing wrong?

Thanks in advance for any help.
 
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16180339887 said:
<br /> [\hat{X}^2,\hat{P}^2]=2i\hbar\left[\left(\hat{X}\hat{P}-i\hbar\right)+\hat{X}\hat{P}\right]=4i\hbar\hat{X}\hat{P}+2\hbar^2<br />

which is wrong because I know from a theorem that if \hat{A} is Hermitian and \hat{B} is Hermitian then [\hat{A},\hat{B}] is anti-Hermitian, which is definitely not the case here. What am I doing wrong?

Maybe, in the last term, when checking whether it's anti-Hermitian, are you
forgetting to swap P and X ?
 
Doesn't 2\hbar^2 destroy the anti-hermicity, since

\left(2\hbar^2\right)^{\dagger}\neq -2\hbar^2
 
16180339887 said:
Doesn't 2\hbar^2 destroy the anti-hermicity, since

\left(2\hbar^2\right)^{\dagger}\neq -2\hbar^2

<br /> (4i\hbar XP + 2\hbar^2)^\dagger ~=~ -4i\hbar PX + 2\hbar^2<br /> ~=~ -4i\hbar(XP - i\hbar) + 2\hbar^2 ~=~ -4i\hbar XP - 4\hbar^2 + 2\hbar^2<br /> ~=~ -(4i\hbar XP + 2\hbar^2)<br />
 
Use the rule:

<br /> [\hat{A}^{2}, \hat{B}^{2}] = [\hat{A}^{2}, \hat{B}] \, \hat{B} + \hat{B} \, [\hat{A}^{2} \, \hat{B}]<br />

and

<br /> [\hat{A}^{2}, \hat{B}] = \hat{A} \, [\hat{A}, \hat{B}] + [\hat{A}, \hat{B}] \, \hat{A}<br />
 
oh you are right i was forgetting to change the order of X and P. Thanks. Thanks for your comment as well Dickfore I will use that.
 

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