Compactness and FIP related problem

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Homework Statement



This question is related to Topology.

Let X be a compact space and let {Ca|a\inA} be a collection of closed sets, closed with respect to finite intersections. Let C = \capCa and suppose that C\subsetU with U open. Show that Ca\subsetU for some a.


The Attempt at a Solution



Here is how my solution goes:

Consider the complement of Ca, X - Ca, is open.
Since X is compact, \cup(X-Ca) is the open cover of X and \cup(X-Ci) for i = 1,2,...,n is a finite subcover of X such that X = \cup(X-Ci).
Now since X is compact and by the finite intersection property, C is nonempty.

But here is where I got stuck...I don't know how to continue to finish the problem.
I think this may be caused by mistakes in my reasoning, but I can't spot it.
Please help me on this question, any help is welcomed.

Thanks in advance.
 
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The closed under finite intersections is important for more than just the fact that C is non-empty. For example, let X=[-2,2], C_1 = [-2,1] and C_2=[-1,2]. Then C=[-1,1]\subset (-\frac{3}{2}, \frac{3}{2} )=U but neither C_1 or C_2 are contained in U
 
Sorry but I still don't quite get it...

So the compactness of X comes into play because now I can generate a open set U that is "big" enough to contain some or all of Ca?
 
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