Comparing Brightness in Series and Parallel Lightbulb Circuits

AI Thread Summary
In comparing brightness in series and parallel lightbulb circuits, bulbs in series receive less current than those in parallel, resulting in dimmer brightness. The total current in a parallel circuit is the sum of the currents through each branch, leading to brighter bulbs. Placing a resistor before Bulb 2 will affect the current distribution, potentially dimming it compared to Bulb 1. The position of the resistor relative to the ammeter does not change the current reading, as it measures total current in the circuit. Understanding these principles is crucial for predicting bulb brightness in different configurations.
IvaNMK
Messages
13
Reaction score
0

Homework Statement


How do the bulb's brightness compare?

Which ones will be brighter or dimmer?

What will happen if a resistor is placed before Bulb 2?
and
What will happen if a resistor is placed between Bulb 2 and 3?

Does it matter if i place the resistor before or after the ammeter? Will it read the same?

Homework Equations



P = IV

R = V/I

The Attempt at a Solution



I think all 3 bulbs will be at the same brightness because current and voltage are the same for both branches.

Thanks for help me out!
Circuit.jpg
 
Physics news on Phys.org
Are these identical bulbs? Are they standard incandescent bulbs?
 
TVP45 said:
Are these identical bulbs? Are they standard incandescent bulbs?

YES, they are.
 
When lightbulbs are in a series, they do not receive as much current as the lightbulb in the parallel series. In other words, the brightnest depends on which lightbulb will receive the current.
 
Kandycat said:
When lightbulbs are in a series, they do not receive as much current as the lightbulb in the parallel series. In other words, the brightnest depends on which lightbulb will receive the current.


you mean that lightbulbs in series receive less current than those in parallel?

Isnt that Current is the same throughout the whole series?

and Total current in parallel circuit is the sum of all currents flowing thru all branches?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top