Comparing Carnot efficiency to Stirling efficiency

AI Thread Summary
The discussion focuses on calculating the efficiency of a Stirling cycle operating between temperatures of Th = 700K and Tc = 400K, using the formula η = W/Qpos. Participants highlight the need to derive work and heat for each leg of the cycle, emphasizing the importance of the molar heat capacity, Cv = 5/2 * R, for diatomic gases. There is a mention of discrepancies in results, with one participant noting their efficiency calculation is significantly lower than expected. Additionally, the efficiency of a Carnot cycle operating at the same temperature extremes is referenced as η = 1 - Tc/Th. Accurate results depend on clarifying the number of moles and the type of gas involved in the calculations.
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Homework Statement



In the problem, we were to derive work and heat for each leg of the cycle. Then we are asked:

In the definition of the efficiency of this cycle, η =W Qpos , where Qpos is the total positive heat flow to the engine, what is the efficiency of the cycle when Th = 700K and
Tc = 400K? V1 = 0.5 L and V2 = 1.5 L. Compare this efficiency to the efficiency of a Carnot cycle that operates between the same temperature extremes.

Homework Equations



Work = integral from Vi to Vf of PdV
W done during cycle = nr(Th-Tc)ln(vf/vi) Derivation here:

http://www.pha.jhu.edu/~broholm/l39/node5.html

Q = Cv(Th -Tc) - nRT ln (Vf/Vi)

We are told Cv = 5/2 * R

efficiency of a carnot cycle = 1- Tc/Th

The Attempt at a Solution



I have attempted to get the solution but have come up with a result that is about an order of magnitude too small that i am unable to rectify. It is part c in the attachment.
 

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CV = 5R/2 is the molar heat capacity at constant volume for a diatomic gas. You need to take account the number of moles when using CV. (You didn't specify if the number of moles is given or whether the gas is monatomic or diatomic.)
 
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