Comparing Forces and Power in a Pulley System: Help with Multiple Choice

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Two identical blocks are lifted at constant velocity by ropes over frictionless pulleys, with Block B moving twice as fast as Block A. The discussion focuses on determining the correct relationship between the forces (FA and FB) and the power supplied (PA and PB) for both blocks. The consensus among participants is that the correct answer is b), indicating that while the forces are equal (FB = FA), the power for Block B is twice that of Block A (PB = 2 PA). This conclusion is based on the principle that power is the product of force and velocity, and since Block B moves at double the speed, its power must also be doubled. Understanding the reasoning behind these relationships is emphasized as crucial for solving similar problems.
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Help please--multiple choice

Two identical blocks are lifted at constant velocity by ropes that run over frictionless pulleys, as shown in the diagram. Block B is raised twice as fast as Block A. The magnitudes of the forces are respectively FA and FB, while the power supplied is respectively PA and PB. Which statement is correct?

a. FB = FA; PB = PA.
b. FB = FA; PB = 2 PA.
c. FB = 2 FA; PB = PA.
d. FB = 2 FA; PB = 2 PA.
e. PA = FA; PB = FB.
 
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I believe it's d).Tell us what u think and bring arguments.That's the only way to check and (probably) correct your reasoning.

Daniel.
 
Phyzix said:
Two identical blocks are lifted at constant velocity by ropes that run over frictionless pulleys, as shown in the diagram. Block B is raised twice as fast as Block A. The magnitudes of the forces are respectively FA and FB, while the power supplied is respectively PA and PB. Which statement is correct?
Since you did not supply the diagram, we can only guess as to the arrangement of the pulleys. Assuming that both ropes run over single pulleys...

What does "constant velocity" tell you about the force needed? How does power depend upon speed?
 
dextercioby said:
I believe it's d).Tell us what u think and bring arguments.That's the only way to check and (probably) correct your reasoning.

Daniel.

d?? I think it's a) - because it is at a constant velocity.
 
futb0l said:
d?? I think it's a) - because it is at a constant velocity.

At equal velocities but different times,does it mean the same force??

Daniel.
 
futb0l said:
d?? I think it's a) - because it is at a constant velocity.
Both d) and a) are half right. :smile: But more important than the answer is the reasoning behind it (as Daniel would say).
 
Ooops - I meant b)... since power is F*v since b has 2v, then the power of b will be twice as much as a. Since it is at equillibrium then Fa = Fb.
 
I agree: b) is the correct answer.
 
Me too. Distance traveled by 1s : Distance traveled by 1s=1:s
Hence PA: PB=1:2
 
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