Comparing mass ratios and 'proving the law of multiple proportions holds true'

AI Thread Summary
The discussion focuses on comparing the mass ratios of N2O3 and N2O5 to demonstrate the law of multiple proportions. The calculations show that for N2O3, the mass of nitrogen is 28g and oxygen is 48g, while for N2O5, nitrogen remains at 28g and oxygen increases to 80g. The resulting mass ratios indicate that the ratio of oxygen in N2O5 to N2O3 is 80g to 48g, simplifying to a ratio of 5:3. This supports the law of multiple proportions, which states that when two elements form different compounds, the ratios of the masses of one element that combine with a fixed mass of the other can be expressed as small whole numbers. Understanding these ratios confirms that the law holds true for these nitrogen oxides.
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Compare the mass ratios of N2O3 and N2O5 and prove the law of multiple proportions holds true.


I'm having trouble understanding what the question is asking for. So far, I've done this:



N2O3:

N: 14g * 2 = 28g

O: 16g * 3 = 48g


N2O5:

N: 14g * 2 = 28g

O: 16g * 5 = 80g


28g N * 80g O = 5
48g O * 28g N = 3

I'm not sure what ratio I found or what to do with those numbers, so any help would be appreciated.
 
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State law of multiple proportions, that will be a good starting point.
 
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