Comparing Momentum and Velocity

  • Thread starter Thread starter Minho
  • Start date Start date
  • Tags Tags
    Momentum Velocity
AI Thread Summary
A car and a truck with equal kinetic energy have a mass ratio of 1:5. The kinetic energy equations reveal that the car's velocity is √5 times that of the truck. Using the momentum formula, the truck's momentum is expressed as Pt = mVt, while the car's momentum, after substituting the velocity, simplifies to Pc = √5 x Vt / 5. This indicates that the car's momentum is less than that of the truck despite its higher velocity. The relationship between momentum and velocity in this scenario highlights the impact of mass on momentum calculations.
Minho
Messages
4
Reaction score
0

Homework Statement



A car and a truck have the same kinetic energy, but the car's mass is one fifth that of the truck. Compare the velocity and momentum of the car with those of the truck.

Homework Equations



KE=1/2mv^2
p=mv

The Attempt at a Solution



I am not really sure what to do here. I tried setting up the Kinetic energy equal to each other, but then the mass and velocity would cancel each other out an I am left with 1/2=1/10. My other method was subtracting the 2 energys, but that doesn't make sense now that I am thinking about it...

Any tips on how to do this?
 
Physics news on Phys.org
Call the truck's mass m and the truck's velocity Vt. What would its kinetic energy be? How about the car's kinetic energy? If you set those equal to each other, you'll get the right answer.
 
ideasrule said:
Call the truck's mass m and the truck's velocity Vt. What would its kinetic energy be? How about the car's kinetic energy? If you set those equal to each other, you'll get the right answer.

so... 1/2m(Vt^2)=1/2(1/5m)(Vc^2)
1/2m(Vt^2)=1/10m(Vc^2)
5(Vt^2)=Vc^2
Square root of 5 x Vt = VC?
 
Yes.
 
All right, now in solving for the potential momentum of the car compared with the truck.

using p=mv, I found the momentum of the truck to be Pt=mVt. I rewrote the equation so that Vt=m/Pt.

I then found the momentum of the car to be Pc=1/5m x (√5 x Vt) <-- velocity of the car. I substituted the Vt so that Pc= 1/5m x √5 x mVt. I canceled out the m's, so all I am left with is Pc= √5 x Vt/ 5.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
9
Views
4K
Replies
6
Views
2K
Replies
4
Views
764
Replies
4
Views
1K
Replies
6
Views
2K
Replies
3
Views
2K
Back
Top