Comparing Rates: Why Don't Units Cancel?

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In summary: The point is that when comparing rates, the units need to be compared somehow.Otherwise, you would have no way of knowing what the rate is.
  • #1
jaketodd
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I know the surface of the Lorentz transformations.

When comparing two rates though, why is it simply not rate over rate (rate/rate)?

Like when comparing two rates of time, due to time dilation, why is it not just time over time (time/time)? I can see that the units would cancel to just 1, and so you'd have no such thing as time. Meters per second compared to different meters per second. (m/s)/(m/s)=unitless. What is the foundation for comparing these so the units don't cancel?
 
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  • #2
jaketodd said:
I know the surface of the Lorentz transformations.

When comparing two rates though, why is it simply not rate over rate (rate/rate)?

Like when comparing two rates of time, due to time dilation, why is it not just time over time (time/time)? I can see that the units would cancel to just 1, and so you'd have no such thing as time. Meters per second compared to different meters per second. (m/s)/(m/s)=unitless. What is the foundation for comparing these so the units don't cancel?
You'll have to explain what you mean by that.
 
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  • #3
If you are writing a ratio of two times, why would you expect the units not to cancel?
 
  • #4
Ibix said:
If you are writing a ratio of two times, why would you expect the units not to cancel?
My question is why is it not just a ratio?
 
  • #5
jaketodd said:
My question is why is it not just a ratio?
Why is what not just a ratio?
 
  • #6
Ibix said:
Why is what not just a ratio?
Ratios of time: s/s. Ratios of rates too like (m/s)/(m/s). You could even have rates of time compared: (s/s)/(s/s).
 
  • #7
Ratios of what times? At the moment, you're just saying "why is a ratio of times not a ratio", which is obviously self-contradictory.
 
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  • #8
jaketodd said:
I know the surface of the Lorentz transformations.

I have no idea what you mean by this; the Lorentz transformations are not the kind of thing that has a "surface".

jaketodd said:
when comparing two rates of time, due to time dilation, why is it not just time over time (time/time)?

Please give a specific example of what you are describing here. A reference would help.
 
  • #9
jaketodd said:
I know the surface of the Lorentz transformations.
PeterDonis said:
I have no idea what you mean by this; the Lorentz transformations are not the kind of thing that has a "surface".
Maybe he means that he has a superficial understanding of Lorentz transformations; i.e., just at the surface level and no deeper.
 
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  • #10
Ibix said:
Ratios of what times? At the moment, you're just saying "why is a ratio of times not a ratio", which is obviously self-contradictory.
Let's say a fast moving object has time slowed down for it from your reference frame. When comparing the elapsing of time for that object, and for you, why is it not just s/s, which cancels to unitless? Hmm, maybe it would be s/s/s = s/s^2 = 1/s. Or (s/s)/(proper time), where proper time is some sort of absolute to compare all clocks to?

Comparing the speed of that object to yourself. Why is it not just (m/s)/(m/s), which cancels to unitless?

Maybe what I'm missing is subtraction. (m/s)-(m/s). And for time, s-s. For some reason I'm thinking division though. Comparing rates of time. (s/s)-(s/s) still cancels to no units.
 
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  • #11
jaketodd said:
Like when comparing two rates of time, due to time dilation, why is it not just time over time (time/time)? I can see that the units would cancel to just 1, and so you'd have no such thing as time.

The geometric analogue of time-dilation is that [itex] \cos\theta= \frac{\mbox{adjacent side}}{\mbox{hypotenuse}} [/itex], which is unitless.
The time-dilation factor (a ratio of two time intervals) is unitless.

In Euclidean geometry, would you say that
"since the units of length cancel to 1, there is no such thing as length?"

As others have suggested, maybe you need a clearer example.
 
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  • #12
jaketodd said:
Let's say a fast moving object has time slowed down for it from your reference frame. When comparing the elapsing of time for that object, and for you, why is it not just s/s, which cancels to unitless? Hmm, maybe it would be s/s/s = s/s^2 = 1/s. Or (s/s)/(proper time), where proper time is some sort of absolute to compare all clocks to?

Comparing the speed of that object to yourself. Why is it not just (m/s)/(m/s), which cancels to unitless?

Maybe what I'm missing is subtraction. (m/s)-(m/s). And for time, s-s. For some reason I'm thinking division though. Comparing rates of time. (s/s)-(s/s) still cancels to no units.
Well, if you are comparing elapsed times by dividing one by the other the result will be dimensionless, as robphy has pointed out. The time between ticks of a clock moving at speed ##v## relative to you divided by the time between ticks of a clock at rest relative to you is ##\gamma=1/\sqrt{1-v^2/c^2}##, which is dimensionless.

I'm not seeing the problem.
 
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  • #13
jaketodd said:
When comparing the elapsing of time for that object, and for you, why is it not just s/s, which cancels to unitless?

How are you comparing the time? If you are just taking the ratio of the times, then it will be unitless, as @Ibix has pointed out.

I don't understand what you think the problem is.
 
  • #14
jaketodd said:
I know the surface of the Lorentz transformations.

When comparing two rates though, why is it simply not rate over rate (rate/rate)?

Like when comparing two rates of time, due to time dilation, why is it not just time over time (time/time)? I can see that the units would cancel to just 1, and so you'd have no such thing as time. Meters per second compared to different meters per second. (m/s)/(m/s)=unitless. What is the foundation for comparing these so the units don't cancel?
Isn’t this just the Lorentz factor?

##γ = \frac{dt}{dτ}##
 
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  • #15
So what is the significance that there are unitless elements in the Lorentz Transformation?

Do they give any insight into what time is or what it isn't?

Maybe something in how those values are derived?

Does knowing how fast a clock ticks require an understanding of time apart from the clock - something to compare it to?
 
  • #16
jaketodd said:
So what is the significance that there are unitless elements in the Lorentz Transformation?
A Lorentz transformation is a type of linear transformation.
A rotation (a certain Euclidean transformation) is a similar type of linear transformation. Its elements are also unitless.
One reason they have to be unitless is that if I apply two rotations in the plane with two angles,
the result is equivalent to a single rotation using the sum of the angles.
So, the elements of the rotation have to be unitless.
This also applies to the Lorentz transformations (where the coordinates are normalized to be of the same type, e.g. (ct,x,y,z)).
jaketodd said:
Do they give any insight into what time is or what it isn't?
It suggests that coordinates of time and of space are inter-related by the symmetry
implied by the principle of relativity (in special relativity and in Galilean relativity).
 
  • #17
jaketodd said:
So what is the significance that there are unitless elements in the Lorentz Transformation?
I think you are still trying to find here some mystery, but there is nothing mysterious about having dimensionless number after dividing two numbers with the same units.
jaketodd said:
Do they give any insight into what time is or what it isn't?
No.
jaketodd said:
Maybe something in how those values are derived?
How is the Lorentz transformation or time dilation derived? There are tons of material out there, textbooks, online lectures etc. Even wiki can provide you some insight.
jaketodd said:
Does knowing how fast a clock ticks require an understanding of time apart from the clock - something to compare it to?
Sure, if you want to claim that some clocks are running at slower rate, you must compare them with some other clocks. How else you could tell?
 
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  • #18
lomidrevo said:
Sure, if you want to claim that some clocks are running at slower rate, you must compare them with some other clocks. How else you could tell?
Seems there needs to be something absolute about time that enables the comparison of clocks.

There are parts to the human brain that keep time: https://www.sciencedaily.com/releases/2005/10/051028142649.htm

If we didn't have those parts of the brain, it seems we wouldn't be able to compare clocks. Same if computers didn't have clocks internally. It's interesting that we use these things to measure something we think is innate in the universe. Well the equations do yield correct results...
 
  • #19
jaketodd said:
Seems there needs to be something absolute about time that enables the comparison of clocks.

There is: proper time. Which in relativity means the invariant arc length along a timelike worldline. "Comparison of clocks" just means comparing the arc lengths along different worldlines.

jaketodd said:
If we didn't have those parts of the brain, it seems we wouldn't be able to compare clocks. Same if computers didn't have clocks internally.

Not at all. Atomic clocks, quartz crystal clocks (like the one that's probably in your wristwatch), and many other kinds of clocks work just fine without any human brains or computers being involved.

jaketodd said:
It's interesting that we use these things to measure something we think is innate in the universe.

In relativity terms, as above, clocks are measuring the arc length along their worldlines. What's the problem?
 
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  • #20
Just funny the reliance on things to try to figure out The things. Like a little piece of brain tissue, ticking, and thereby drawing conclusions about the nature of all things.
 
  • #21
jaketodd said:
If we didn't have those parts of the brain, it seems we wouldn't be able to compare clocks. Same if computers didn't have clocks internally. It's interesting that we use these things to measure something we think is innate in the universe. Well the equations do yield correct results...
"these things" are part of the universe, and obeying its laws, including the implications of special relativity. So why not?

The most simple clocks you could imagine are probably light clocks. I suggest you read this part of Feynman lecture. The mechanism of other clocks like for example human body, quartz or atomic clocks, is generally more complicated. But all of them can be (and really are) used to measure the time.

Side note:
I do not recommend to read further parts of the suggested lecture, beginning by 15–8 Relativistic dynamics. Feynman used a concept of "relativistic mass" which is now depreciated.
 
  • #22
Seems like a scavenger hunt. We are not provided with the laws. No we have to go out using ourselves as tools to learn the laws. I guess it's more exciting that way.
 
  • #23
jaketodd said:
Meters per second compared to different meters per second. (m/s)/(m/s)=unitless. What is the foundation for comparing these so the units don't cancel?

You can do it either way. The choice is arbitrary. You can say that the speed of planet Earth in its orbit about the sun is 30 km/s. Or you can compare it to the speed of light, 300 000 km/s, and say that its speed is one ten-thousandth the speed of light.

Every measurement is a comparison to a standard, so this can be done with any measurement.
 
  • #24
Someone says clock A ticks twice as fast as clock B. So 5 seconds of clock B is 10 seconds on clock A. So it could be said that (2 x clock B) / (1 x clock A). The unit of seconds would cancel. I think you guys already answered this as I am thinking of a ratio, that is normally unitless? Just seems like a rate of time would involve division and the units would cancel, so how is there any comparing time?
 
  • #25
jaketodd said:
I think you guys already answered this

Yes, your question has been answered. Repeatedly. Continuing to repeat the same answers doesn't seem like a good use of anyone's time.

Thread closed.
 

1. Why don't units cancel when comparing rates?

Units do not cancel when comparing rates because rates are ratios of two different quantities with different units. The units need to be included in the calculation to ensure that the final result has the correct units.

2. Can I still compare rates if the units are different?

Yes, you can still compare rates even if the units are different. This is because rates are ratios and as long as the units are consistent in the numerator and denominator, the units will cancel out and the result will be a pure number.

3. How do I compare rates with different units?

To compare rates with different units, you need to convert one of the rates to have the same units as the other rate. This can be done by using conversion factors or unit conversions. Once the units are the same, you can compare the rates as you normally would.

4. Why is it important to compare rates?

Comparing rates is important because it allows you to determine which rate is faster, slower, or equal to another rate. This is useful in many real-world situations such as comparing prices, speeds, or quantities.

5. What are some real-life examples of comparing rates?

Some real-life examples of comparing rates include comparing the cost per ounce of different products at the grocery store, comparing the speed of different modes of transportation, or comparing the amount of time it takes to complete a task using different methods.

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