Compass deflection by overhead transmission lines

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SUMMARY

The discussion focuses on calculating the magnetic field produced by an overhead transmission line and the resulting compass deflection. The magnetic field strength directly underneath the wire, carrying a current of 807A, is determined to be 3.164 x 10^-5 T using the formula for a straight conductor. The deflection angle of the compass, influenced by both the Earth's magnetic field and the field from the transmission line, is calculated to be approximately 33 degrees. This analysis employs vector addition to find the resultant magnetic field direction.

PREREQUISITES
  • Understanding of magnetic fields, specifically the formula for a straight conductor.
  • Familiarity with vector addition and trigonometric functions.
  • Basic knowledge of Earth's magnetic field strength (0.5 x 10^-4 T).
  • Ability to interpret and analyze magnetic field interactions.
NEXT STEPS
  • Study the principles of magnetic fields generated by current-carrying conductors.
  • Learn about vector addition in physics, particularly in the context of magnetic fields.
  • Explore the effects of electromagnetic fields on compass readings.
  • Investigate the applications of magnetic field calculations in real-world scenarios, such as electrical engineering.
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in understanding the interaction between magnetic fields and compass navigation under electrical infrastructure.

SQUIDDO
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Problem Description:
A hiker is reading a compass under an overhead transmission line that is 5.1m above the ground and carries a current of 807A in a horizontal direction from North to South. Assume the Earth's field is of the order 0.5*10^-4T.

A) Determine the magnitude of the field produced by the transmission line at a point directly underneath

B) Due to the transmission line, the compass will be deflected by a certain angle instead of pointing north. Find this angle in degreesRelevant equations:
1. Magnetic field of a straight conductor at distance 'd' = (μ/4π)*(2I/d)
Attempt at Solution:
Using the equation above and a given value for mu, I was able to find the strength of the magnetic field directly underneath the wire as being 3.164*10^-5

As for the next step, I'm totally lost. I was thinking of finding the forces on the compass due to the transmission line compared to Earth's field, and using vector lines to find the deflection, but I have no idea of the charge on the compass or anything.

I also thought I could just take the relative directions and sizes of the Earth's field and then draw vectors from there, but I don't know if that's allowed.

What can I do? Thanks for your time!
 
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SQUIDDO said:
I also thought I could just take the relative directions and sizes of the Earth's field and then draw vectors from there, but I don't know if that's allowed.
Yes, it's allowed :smile:. What do you get? (You don't need the "charge" of the compass. Just figure out the direction of the net magnetic field.)
 
In that case, I draw two vectors to represent the magnetic field directly under the wire due to the wire (A), and due to the Earth (B).

Assembling them head-to-tail, tan(theta) = B/A
So theta must be ~33 degrees, which is right! Thanks!
 

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