Complete Square + Leibniz question (2 questions)

AI Thread Summary
The discussion focuses on two main questions regarding completing the square in equations and the cancellation of units in Leibniz notation. Participants express confusion about the thought process behind completing the square and how it seems to emerge without clear steps. They also explore the relationship between distance, velocity, and time, specifically how dividing these quantities results in a time unit. The conversation highlights the need for clarity in manipulating equations and understanding the notation used. Overall, the thread emphasizes the importance of careful algebraic manipulation and unit analysis in solving these mathematical problems.
Craig Scott
Messages
10
Reaction score
2

Homework Statement


1. How did they complete the square for these equations in the picture below? What was their thought process?

2. distance/velocity = time , velocity/acceleration = time , In leibniz notation how does this cancel out?

When you divide, how does it cancel out to give you a time unit?

Homework Equations


1. In picture

2. ds/dt / d2s / dt2

The Attempt at a Solution


1. It seems like it came out of thin air.

2. dt/ds = time?
 

Attachments

  • completesq.jpg
    completesq.jpg
    34.1 KB · Views: 536
Physics news on Phys.org
What is 2. in your relevant equations?

##V = d/t \to t = d/V##
You can add A and subtract A (equivalent to adding 0), and it's still the same.
##\frac{v_{y0}x}{v_{x0}} - \frac{gx^2}{2v_{x0}^2} + \frac{v_{y0}^2}{2g} - \frac{v_{y0}^2}{2g} ##
They factored out ## \frac{-g}{2v_{x0}^2} ##

Rearrange it and it might look a little closer.
 
In my relevant solutions it is velocity/acceleration, the way I put it was just in leibniz notation in terms of s(t)
 
I think I was just confused by all the slashes. Sort of makes it look like one big fraction made of fractions.
 
V2y0/2g

How did you find that
 
Craig Scott said:
V2y0/2g

How did you find that
I assume you are asking about getting from the second equation in the image to the third.
Just expand the square in the third equation and simplify. You should arrive at the second equation.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top