Completing the Square with Coefficient on X^2

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The discussion focuses on completing the square for the equation involving various quadric surfaces, specifically when dealing with negative coefficients. The user struggles with how to handle the negative coefficient for the y-term while completing the square. Clarifications are provided on how to maintain balance in the equation when adding terms, emphasizing the importance of tracking added values. The conversation highlights the necessity of factoring out the negative coefficient to simplify the process. Ultimately, understanding these steps is crucial for accurately transforming the equation into its standard form.
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Homework Statement



Consider all possible surfaces that can be formed from the variations of

\[PlusMinus]x^2\[PlusMinus]4y^2\[PlusMinus]z^2+2x+8y+6z==-6,

that is, find and describe all the different quadric surfaces you can make from this equation by using different signs on the degree 2 terms. For each one, find the standard form of the equation.

I am having problems completing the square when the coefficient is negative.

The Attempt at a Solution



For the case where the y-coefficient is negative:

(x^2 + 2x + 1) + (-4y^2 + 8y + _ ) + (z^2 +6z + 9) = -6 + 1 + _ + 9

dividing by -4 gives: (y^2 - 2y + _ )

Adding (b/2a)^2: (y^2 - 2y + 1)

Condensing: (y - 1)^2

Now, does the coefficient 4 come back as positive or negative, as in
4(y - 1)^2 or -4(y - 1)^2

Also, when adding to the other side of the equation, does the -4 multiply to the added quantity?

Thanks for any help
 
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(-4y2 + 8y )
= -(4y2 - 8y + __) + something

You're going to add a positive number inside the parentheses, but you have really added a negative number, so to keep the expression in balance, add the positive of that negative number.

Make sense?
 
What else you should do to make your life simpler is to bring out the coefficient on the 2nd degree term so that you have
-4(y2 - 2y + __) + something

Just keep track of what you really added to the overall expression.
 
Okay, thanks for helpin me out
 
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