Completing the squares of a multivariable function

AI Thread Summary
The discussion focuses on completing the square for the multivariable function x^2 + y^2 + 2xy - 2x - 2y + 43 = 0. The solution provided successfully simplifies the expression to the form ((x + y) - 1)^2 + 42. Participants express satisfaction with the method used, indicating it is already a "nice" approach. There is a request for alternative methods, but the existing solution is deemed effective. Overall, the completion of the square is confirmed as a valid and aesthetically pleasing technique.
pondzo
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Homework Statement



completing the squares; ## x^2+y^2+2xy-2x-2y+43 = 0##

The Attempt at a Solution



I did it as follows, but i would like to know if there is a different 'nicer' method to complete it;

## x^2 + y^2 + 2xy − 2x − 2y + 43 ##

## = (x + y)^2 − 2x − 2y + 43 ##

## = (x + y)^2 − 2(x + y) + 43 ##

## = (x + y)^2 − 2(x + y) + 1 + 42 ##

## = ((x + y) − 1)^2 + 42 ##
 
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pondzo said:

Homework Statement



completing the squares; ## x^2+y^2+2xy-2x-2y+43 = 0##

The Attempt at a Solution



I did it as follows, but i would like to know if there is a different 'nicer' method to complete it;

## x^2 + y^2 + 2xy − 2x − 2y + 43 ##

## = (x + y)^2 − 2x − 2y + 43 ##

## = (x + y)^2 − 2(x + y) + 43 ##

## = (x + y)^2 − 2(x + y) + 1 + 42 ##

## = ((x + y) − 1)^2 + 42 ##
That looks plenty "nice" to me !
 
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