Complex Analysis: Evaluating an Integral over a Contour

beefcake24
Messages
16
Reaction score
0
Evaluate the integral of f over the contour C where:

f(z) = 1/[z*(z+1)*(z+2)] where C = {z(t) = t+1 | 0 <= t < infinity}

Over this contour, is f a real valued function? z(t) just maps t to the t+1, so it seems as if the contour is a real-valued continuous function, and f does not have any explicit imaginary parts in it that are dependent on t. I was able to get f into partial fractions, but was a little confused about this.

Any help would be greatly appreciated, as I have a midterm on this stuff tomorrow.

Thanks!
 
Last edited:
Physics news on Phys.org
Yes, z is real. No, z is not "the next incremented real number"- there is no "next" number" in the real numbers. Since t goes from 0 to infinity, z goes from 1 to infinity. This integral is just the real integral
\int_1^\infty \frac{dz}{z(z+1)(z+2)}
which can be done by "partial fractions". No complex numbers involved at all.
 
Haha yeah, I definitely worded that incorrectly, just edited my original post. Thanks for the reply, that's exactly what I needed!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top