Complex Analysis - Proving an inequality

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Homework Help Overview

The problem involves proving an inequality related to complex numbers, specifically showing that if |z| = 10, then 497 ≤ |z^{3} + 5iz^{2} − 3| ≤ 1503.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the triangle inequality to establish bounds for the expression involving z. There is uncertainty about how to correctly apply the inequalities and whether substituting specific values for z is appropriate.

Discussion Status

Some participants are exploring different approaches to apply the triangle inequality, while others express confusion about the implications of their attempts. There is a recognition that multiple interpretations of the problem exist, and some guidance has been offered regarding the use of inequalities.

Contextual Notes

Participants note that |z| = 10 allows for various values of z, which raises questions about the generality of specific substitutions made in attempts to solve the problem.

NewtonianAlch
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Homework Statement


Show that if |z| = 10 then 497 ≤ |z[itex]^{3}[/itex] + 5iz[itex]^{2}[/itex] − 3| ≤ 1503.



The Attempt at a Solution



I'm not an entirely sure how to begin this one, or if what I'm doing is correct.

If I sub in |z| = 10 into the equation; |1000 + 500i - 3| = 997 +500i

Then the modulus of that is sqrt(997[itex]^{2}[/itex]+500[itex]^{2}[/itex]) = 1115.35

497 ≤ 1115.35 ≤ 1503
 
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You subbed in z=10, but there are many other values of z with |z|=10 (for example, 10i, 5sqrt(2)+5sqrt(2)i, etc.)

You just have to apply the triangle inequality (in a different form for each bound)
 
I took a look at triangle inequalities for Complex Analysis, and there are essentially two types?

One for the upper bound and one for the lower:

|z1 + z2| ≤ |z1| + |z2|

|z1 + z2| ≥ ||z1| − |z2||

But I'm not too sure how that would fit in here.

Would I need to find the roots of z as a starting point?
 
NewtonianAlch said:
|z1 + z2| ≤ |z1| + |z2|

For example, from this you can also show
[tex]| z_1 + z_2 + z_3 | \leq |z_1| + |z_2| + |z_3|[/tex]
 
It's really not clicking still.

So I'm meant to show 497 ≤ |z1| + |z2| + |z3|, so would z1 = z^3, z2 = 5iz^2, and z3 = -3 ?
 
NewtonianAlch said:
It's really not clicking still.

So I'm meant to show 497 ≤ |z1| + |z2| + |z3|, so would z1 = z^3, z2 = 5iz^2, and z3 = -3 ?

That wouldn't prove anything, since 497 ≤ |z1| + |z2| + |z3| does not imply that 497 ≤ |z1 + z2+ z3|

However, the other direction might be more fruitful
 
OK.

|z1 + z2 + z3| [itex]\geq[/itex] 497

z1 = z^3
z2 = 5iz^2
z3 = -3

z^3 + 5iz^2 [itex]\geq[/itex] 500
|z| = 10, so |z|^2 = 100

Simplifying equation to 1 + 5i [itex]\geq[/itex] 1/2

Am I even remotely in the right direction?

Really appreciate your help by the way. Thanks for that.
 
I'm still stuck on this problem if anyone can help that'd be great =)
 
Nvm, it is solved now! Can't believe it was actually very easy, once the tutor did it in class, I was like doh!
 

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