Complex Impedance: Solve Homework Problem

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SUMMARY

The discussion focuses on calculating the complex impedance of a circuit containing a capacitor and a resistor. Given a voltage across the capacitor of 3.2V, a voltage across a 47Ω resistor of 4.65V, and a current of 0.0989A with a phase difference of 90 degrees, the complex impedance is derived using the formula Z = R + jX. The participant successfully applies their algebra skills to solve for the impedance, confirming their understanding of the relationship between voltage, current, and impedance in AC circuits.

PREREQUISITES
  • Understanding of complex impedance in AC circuits
  • Familiarity with Ohm's Law and Kirchhoff's laws
  • Knowledge of phasors and phase differences
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the concept of phasor representation in AC circuit analysis
  • Learn about the relationship between impedance, voltage, and current in RLC circuits
  • Explore the use of complex numbers in electrical engineering
  • Investigate the impact of phase differences on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone studying AC circuit analysis will benefit from this discussion.

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Homework Statement


In a circuit consisting of a capacitor (Voltage across is 3.2V) and a 47\Omegaresistor (Voltage across is 4.65V), with a current of 0.0989A and a phase difference between the two voltages being 90', what is the complex impedance for the circuit?

Unsure of how to work this out, the stated values are ones I have worked out and may not necessarily be useful to this problem.

Homework Equations


The Attempt at a Solution


Wouldn't know where to start
 
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Z = R +jX=R-j\frac{|V_c|}{|I_c|}
 
Thanks a ton, I think I get it now, had to brush up on a bit of my old algebra notes.
 

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