Complex number question (i think )

AI Thread Summary
The discussion revolves around solving the quadratic equation z^2 + 3z + 2 = 0, which has been factored into (z+1)(z+2)=0, yielding solutions z = -1 and z = -2, both of which are real numbers and thus valid in the complex number system. The participant expresses confusion about the requirement to express solutions in the form of x + iy, but it is clarified that the solutions can be represented as x + 0i. A second equation, z^2 + 2z + 1 = 0, is mentioned, which involves a conjugate and is noted to have four complex solutions, indicating a higher level of complexity. The advice given emphasizes mastering simpler problems before attempting more challenging ones to avoid confusion. Understanding the basics of complex numbers is essential for tackling these equations effectively.
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Complex number question (i think :) )

Homework Statement



Solve the following equations in C :

(a) z^2 + 3z + 2 = 0

The Attempt at a Solution



I thought i should solve the quadratic for z, (z+1)(z+2)=0
and then somehow say that:

1=x+iy

I don't really understand how to go about it, and they want it solved in C. Any hints wil be greatly appreciated!

p.s

This question is a few exercises down, and i know i don't know how to tackle it, it confuses me pretty bad having the conjugate there aswell:

z^2 + 2z + 1 = 0 (where the second z is the conjugate)

Thanks!
 
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So you've factorized the quadratic into (z+1)(z+2). So what are the zeroes of the quadratic then? You've basically solved the question, and even though no complex numbers arised, it is still in C. The solutions are of the form x+0i.

The second question with the conjugate is more difficult. There are actually 4 complex solutions to that equation.
You better get a good grip of the easier questions before tackling those ones or you'll just confuse yourself.
 
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