- #1

- 3

- 0

I am having trouble solving the sqrt 3i part. I think I need to use de moivres theorem but I am unsure. If someone could push me in the right direction that would be a massive help. Thanks.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter JC_003
- Start date

- #1

- 3

- 0

I am having trouble solving the sqrt 3i part. I think I need to use de moivres theorem but I am unsure. If someone could push me in the right direction that would be a massive help. Thanks.

- #2

Cyosis

Homework Helper

- 1,495

- 0

What's the question exactly? You want to write that complex number in its polar representation or as x+iy? Either way start with writing [itex]1-\sqrt{(3i)}[/itex] in the polar representation. Once you have that it is easy to compute [itex](1-\sqrt{(3i)})^3[/itex].

Last edited:

- #3

- 365

- 0

[tex]\sqrt[3]{1-i\sqrt{3}}[/tex]

Use De Moivre's theorem to find all the solutions.

- #4

- 3

- 0

If z= 5 +4i, write the number z(|z|^2-(1- sqrt3i)^3) in the form a+bi.

I am able to sub everything in but I want to simplify the (1- sqrt3i)^3. The square root has thrown me off.

- #5

Cyosis

Homework Helper

- 1,495

- 0

- #6

- 3

- 0

- #7

Cyosis

Homework Helper

- 1,495

- 0

- #8

- 286

- 0

[tex](\sqrt{3})i[/tex]

or

[tex]\sqrt{(3i)}[/tex]

Huge difference.

The question is not clear enough for me to help effectively, but I suspect -8 shows up somewhere.

--Elucidus

Share: