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Ry122
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For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus?
Ry122 said:For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus?
An intercept is a point where a line or curve crosses either the x-axis or the y-axis on a graph. It is also known as a root or a zero.
To find the x-intercept of z3=3e^(-ipie/4), we set z3 equal to 0 and solve for x. This can be done by taking the natural logarithm of both sides and using the properties of logarithms to isolate x.
The modulus of a complex number is its distance from the origin on the complex plane. It is also known as the absolute value or magnitude of a complex number.
To find the modulus of z3=3e^(-ipie/4), we use the Pythagorean theorem by taking the square root of the sum of the squares of the real and imaginary parts of the complex number. In this case, the modulus is equal to 3.
The angle, -ipie/4, in the exponential term of z3=3e^(-ipie/4) represents the direction and rotation of the complex number on the complex plane. It is also known as the argument or phase angle of the complex number.