For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus?
Apr 6, 2008 #1 Ry122 565 2 For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus?
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Apr 6, 2008 #2 Pere Callahan 586 1 Ry122 said: For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus? I don't understand how this is supposed to be a function. What is your independent variable..? z..? z3..? z^3..?
Ry122 said: For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus? I don't understand how this is supposed to be a function. What is your independent variable..? z..? z3..? z^3..?
Apr 6, 2008 #5 Pere Callahan 586 1 Still, [itex]z=3e^{-i\pi \frac{e}{4}}[/itex] is not a function but some fixed constant number.