Composite function and continuerty

Mathman23
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Hello I have the following problem:

Given two function f and g which are continuer on R, and some point c which belongs to R.

I'm suppose to show that if f(c) = g(c), then h is continious on R.

Isn't that the same as showing that that the composite function

h(c) = g(f(c)) is continues on R?

Best Regards,

Fred
 
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Given two function f and g which are continuer on R, and some point c which belongs to R.

I'm suppose to show that if f(c) = g(c), then h is continious on R.

You haven't told us what "h" is.
 
Muzza said:
You haven't told us what "h" is.

h is definied as follows

<br /> \begin{displaymath}<br /> h(c) = \left\{ \begin{array}{ll}<br /> f(c) \\<br /> g(c) \\<br /> \end{array} \right.<br /> \end{displaymath}<br />


c \in \mathbb{R} and f and g er continious on R.

Then how do I show that if f(c) = g(c), then h(c) is continious on R?

My own ideer is to show this if f and g are continious on R, then the composite function h is continious on R.

Best Regards

/Fred
 
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I'm afraid I have no idea what that means.
 
Okay let's look it at another way,

f and g: [a,b] \rightarrow \mathbb{R} are continious, c \in ]a,b[. Next, let h be

\begin{displaymath}h(x) = \left\{ \begin{array}{ll}f(x) \ \ \ \\g(x) \\\end{array} \right.\end{displaymath}

h is defined on [a,b]

Now my assigment is the following:

a) Let f and g be arbitrary functions. Show that if f(c) = g(c), then the function h is continious. I sure I need to use the epsilon-delta definition of continuerty, but if there is anybody out there who maybe can explain what I need to do by way of an example I would very much appreciate it :-)

b) If f(c) \neq g(c) the h is discontinious. Anybody who can direct me to a good example on how to show this?

Sincerely and God bless You :-)

Fred

/Fred
 
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