Lynne
- 12
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Hi,
Given:f(x)=x^2+2 and g (x)=\sqrt{x}
Find: f \circ g and g \circ f
2. The attempt at a solution
f \circ g =f(g(x))=x+2, where x\in (-\infty ; +\infty)
g \circ f =g(f(x))=\sqrt{x^2+2} where x\in (-\infty ;+ \infty)
I haven't done this for a while, and I'm not sure about my solution. Is it correct?
Homework Statement
Given:f(x)=x^2+2 and g (x)=\sqrt{x}
Find: f \circ g and g \circ f
2. The attempt at a solution
f \circ g =f(g(x))=x+2, where x\in (-\infty ; +\infty)
g \circ f =g(f(x))=\sqrt{x^2+2} where x\in (-\infty ;+ \infty)
I haven't done this for a while, and I'm not sure about my solution. Is it correct?