What is the domain of f(f(x)) for f(x)= x/(1+x)?

AI Thread Summary
The function f(x) = x/(1+x) leads to f(f(x)) = x/(1+2x). The initial domain found was incorrect; the correct domain is (-∞,-1)∪(-1,-1/2)∪(-1/2,∞). The mistake was in not accounting for the values that make f(f(x)) undefined, specifically when x = -1/2. The intersection of the domains must be carefully calculated to ensure all restrictions are considered. Understanding these domain restrictions is crucial for accurately determining the function's behavior.
Jpyhsics
Messages
84
Reaction score
2

Homework Statement


f(x)= x/(1+x)

What is f(f(x)) and what is its domain.

2. The attempt at a solution
I found f(f(x))= x/(1+2x)
and the domain: (-∞,-1/2)∪(-1/2,∞) , but it is saying that I have the wrong domain. What mistake have I made?


My process for finding domain:
1. Find the domain of f : x≠-1
2. Use the definition D: {x∈(-∞,-1)∪(-1,∞) | (x/1+x) ≠ -1}
3. Find the ∩ (intersection) for the two domains.
 
Physics news on Phys.org
Jpyhsics said:

Homework Statement


f(x)= x/(1+x)

What is f(f(x)) and what is its domain.

2. The attempt at a solution
I found f(f(x))= x/(1+2x)
and the domain: (-∞,-1/2)∪(-1/2,∞) , but it is saying that I have the wrong domain. What mistake have I made?


My process for finding domain:
1. Find the domain of f : x≠-1
2. Use the definition D: {x∈(-∞,-1)∪(-1,∞) | (x/1+x) ≠ -1}
3. Find the ∩ (intersection) for the two domains.

What is ##f(f(-1)##?
 
  • Like
Likes SammyS
PeroK said:
What is ##f(f(-1)##?
Oh I see! Its undefined!
So I guess my domain should be (-∞,-1)∪(-1,-1/2)∪(-1/2,∞)

Thank You!
 
  • Like
Likes Delta2
Jpyhsics said:
Oh I see! Its undefined!
So I guess my domain should be (-∞,-1)∪(-1,-1/2)∪(-1/2,∞)

Thank You!

Formally: if ##D_1 = A \cup B## and ##D_2 = C \cup D## then $$ D_1 \cap D_2 = (A\cap C) \cup (A \cap D) \cup (B \cap A) \cup (B \cap D)$$ Apply this to ##A = (-\infty,-1),## ##B = (-1,\infty)##, ##C = (-\infty, -1/2)## and ##D = (-1/2,\infty).##
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top