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## Homework Statement

Computer the volume of the solid bounded by the xz plane, the yz plane, the xy plane, the planes x = 1 and y = 1, and the surface z = x

^{2}+ y

^{2}

## Homework Equations

None.

## The Attempt at a Solution

Since the solid is bounded by the xz plane, the yz plane, the xy plane, it is assumed that the values of x, y, and z all equal 0. And since x = 1 and y = 1, the limits of integration is:

0 [tex]\leq[/tex] x [tex]\leq[/tex] 1

0 [tex]\leq[/tex] y [tex]\leq[/tex] 1

Thus, the double integral is:

[tex]\int[/tex] [tex]\int[/tex] x

^{2}+ y

^{4}dA

and the limits of integration is 0 [tex]\leq[/tex] x [tex]\leq[/tex] 1, 0 [tex]\leq[/tex] y [tex]\leq[/tex] 1.

After calculating the integral, I got the answer [tex]\frac{8}{15}[/tex]. Can anyone verify my work?