Computing the moment of inertia for a rotary inverted pendulum

  • Thread starter Thread starter Remusco
  • Start date Start date
AI Thread Summary
The discussion centers on calculating the moment of inertia for a rotary inverted pendulum, specifically about the motor shaft. The original poster seeks a derivation or formula, assuming uniform rods for both the pendulum and motor arm while neglecting the inertia of the motor shaft and rotary encoder. Participants emphasize the need for a labeled diagram to clarify the variables used in the relevant equations, which include the total moment of inertia formula. The conversation highlights the importance of defining parameters like mass and length for accurate calculations. Overall, the thread aims to assist in deriving the moment of inertia based on the specified system configuration.
Remusco
Messages
30
Reaction score
3
Homework Statement
Compute the moment of inertia seen by the motor shaft for a rotary inverted pendulum
Relevant Equations
I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2
I looked all over the internet and I can't find a derivation of this. It is over my head to derive this.
This is my system:
1743111571615.png


I want to assume that the pendulum and motor arm are uniform rods. I want to ignore the motor shaft inertia and the rotary encoder inertia since they are negligible. Does anyone have the formula for J about the motor shaft? I imagine this is dependent on the angle of the pendulum.
 
Physics news on Phys.org
Remusco said:
Homework Statement: Compute the moment of inertia seen by the motor shaft for a rotary inverted pendulum
Relevant Equations: I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2

I looked all over the internet and I can't find a derivation of this. It is over my head to derive this.
This is my system:
View attachment 359080

I want to assume that the pendulum and motor arm are uniform rods. I want to ignore the motor shaft inertia and the rotary encoder inertia since they are negligible. Does anyone have the formula for J about the motor shaft? I imagine this is dependent on the angle of the pendulum.
Hi, please wrap your text with Latex tags ##'s.
 
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##

You need to post a labeled diagram of your system. How can we possibly assist if we don't know the meanings of the symbols ##I_m,m_a,l_a,m_p,l_p,\theta_{i-1}##?
 
renormalize said:
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##

You need to post a labeled diagram of your system. How can we possibly assist if we don't know the meanings of the symbols ##I_m,m_a,l_a,m_p,l_p,\theta_{i-1}##?
I assume this is effectively a continuation of https://www.physicsforums.com/threads/simulating-a-rotary-inverted-pendulum-in-python.1079126/
 
  • Informative
  • Like
Likes berkeman and renormalize
renormalize said:
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##
OK, thanks to @haruspex I've found your previous post that defines most of the variables in your Relevant Equation:
Remusco said:
# System Parameters
m_p = 0.1 # Mass of pendulum (kg)
m_a = 0.5 # Mass of arm (kg)
l_p = 0.2 # Length of pendulum (m)
l_a = 0.15 # Length of arm (m)
g = 9.81 # Gravity (m/s^2)
b = 0.00 # Damping coefficient
I_a = (1/3) * m_a * l_a**2 # Arm moment of inertia
I_p = (1/3) * m_p * l_p**2 # Pendulum moment of inertia
And from the photo of your apparatus in post #1 I surmise that the following is a reasonable representation of your inverted pendulum (but without the Mass at the end of the pendulum rod):
1743140223464.png

(From: https://www.st.com/content/dam/AME/...to_Integrated_Rotary_Inverted_Pendulum_v2.pdf)
If my surmise is correct, can you attempt to write down the formula for the moment-of-inertia ##I_{\text{total}}## seen by the Motor-shaft, in terms of the variables ##r,l,\theta,\phi## shown in Fig. 1 and the masses of the Rotor and Pendulum rods?
 
renormalize said:
OK, thanks to @haruspex I've found your previous post that defines most of the variables in your Relevant Equation:

And from the photo of your apparatus in post #1 I surmise that the following is a reasonable representation of your inverted pendulum (but without the Mass at the end of the pendulum rod):
View attachment 359098
(From: https://www.st.com/content/dam/AME/2019/Educational Curriculums/motor-control/Introduction_to_Integrated_Rotary_Inverted_Pendulum_v2.pdf)
If my surmise is correct, can you attempt to write down the formula for the moment-of-inertia ##I_{\text{total}}## seen by the Motor-shaft, in terms of the variables ##r,l,\theta,\phi## shown in Fig. 1 and the masses of the Rotor and Pendulum rods?
Yes this is what I am looking for. Thanks for clarifying.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top