Concentration and pressure problem. Need help

AI Thread Summary
The discussion focuses on calculating the total pressure at equilibrium for the decomposition of ammonium carbamate (NH2COONH4) into ammonia (NH3) and carbon dioxide (CO2) in a specified volume. At 442 K, the equilibrium constant Kc is given as 0.043, with a concentration of NH2COONH4 calculated at 0.2613. The correct total pressure at equilibrium for 10.2 g of ammonium carbamate in a 0.500 L container is determined to be 2.40E1. Additionally, a similar problem is posed regarding the introduction of ammonium carbamate into a 0.400 L container at 37 ºC, where Kc is 4.1. The thread seeks assistance in deriving the equilibrium constant expression and solving for the total amount of ammonium carbamate at equilibrium.
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Ammonium carbamate (NH2COONH4) is found in the blood and urine of mammals. At a temperature of 442 K, Kc = 0.043 for the following equilibrium:
NH2COONH4(s) <=> 2 NH3(g) + CO2(g).
If 10.2 g of ammonium carbamate is introduced into a 0.500 L container, what is the total pressure inside the container at equilibrium?

Correct answer 2.40E1 (2.40 * 101)

Concentration of NH2COONH4: 0.2613

If someone would help me, I would very much appreciate it.
 
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first write out the equilibrium constant expression
 
Concentration problem. Need help!

Ammonium carbamate (NH2COONH4) is introduced into a 0,4 L container, at a temperature of 37 ºC, Kc = 4,1 for the following equilibrium:
NH2COONH4(s) <=> 2 NH3(g) + CO2(g).
What is total of ammonium carbamate is introduced into a 0.400 L container at equilibrium?
 
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