While waiting for my other post to be moved, I'm putting this question up again. 25.00 mL of .1857 M Ba(OH)2 reacts with 30.00mL of .2228M NiSO4. Find the concentration of all ions after the reaction assuming that final volume is the sum of the initial volumes. Ba(OH)2 + NiSO4 -> BaSO4 + Ni(OH)2 The answer is .03629M Ni2+ and .03629M SO42- [Ba2+] = [OH-] is about zero. How are these answers found? How would the concentrations change after the reaction? Please help. No specifics are needed just a general guide to figure this out. I may regret saying that.