Concentrations of Pb2+ and Cl2 at equilibrium

  • Thread starter Thread starter magma_saber
  • Start date Start date
  • Tags Tags
    Equilibrium
AI Thread Summary
To find the concentrations of Pb2+ and Cl2 at equilibrium after mixing 50.0 mL of 0.36 M Pb(NO3)2 with 50.0 mL of 1.7 M KCl, the Ksp for PbCl2 (1.6 x 10-5) must be used correctly. The initial moles of Pb(NO3)2 and KCl are calculated as 0.018 mol and 0.085 mol, respectively. The discussion emphasizes that the Ksp formula should be based on the concentrations of the ions, not the original compounds. After precipitation occurs, the remaining excess ion concentration can be used to calculate the equilibrium concentration of the other ion. Understanding the limiting reagent concept is crucial for solving this problem accurately.
magma_saber
Messages
73
Reaction score
0

Homework Statement


A solution is prepared by mixing 50.0 mL of 0.36 M Pb(NO3)2 with 50.0 mL of 1.7 M KCl. Calculate the concentrations of Pb2+ and Cl2 at equilibrium. Ksp for PbCl2(s) is 1.6 x 10-5.


Homework Equations


I think its Ksp = [Pb(NO3)2][KCl]2

Pb(NO3)2 = 0.018 mol
KCl = 0.085 mol

Is this right? what do i solve for?
 
Physics news on Phys.org


Your Ksp is wrong. It should be made of ions concentrations.

Otherwise it is limiting reagent question. Once everything precipitates out, you will be left with the excess of one of the ions involved. Use this concentration to calculate concentration of the other using (correct) Ksp formula.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top