Conceptual question about currents and pumps

1. Mar 18, 2007

asdf916

1. The problem statement, all variables and given/known data

2. Relevant equations

I suppose the energy density equation applies here:

(P2-P1) + pg(y2-y1) + 1/2p(v2^2 - v1^2) = Epump/vol - IR

and

I = Av

3. The attempt at a solution

My initial thought was that the current is the same. But then, since current is Av, I was second guessing myself that maybe the velocities are different. Any help's appreciated!

2. Mar 18, 2007

asdf916

Also, I'd appreciate it if you guys can help me on these

My guess was that the sewer gas is less than 1 ATM.

My guess is that the pressures are the same. Using the same energy density equation on the first post, I could eliminate the KE, Epump, and IR. That leaves the pressure and the PE. Since it's measuring the same height, the pressure's the same. Is this correct?