Conceptual question about currents and pumps

[asdf916]

Homework Statement

Homework Equations

I suppose the energy density equation applies here:

(P2-P1) + pg(y2-y1) + 1/2p(v2^2 - v1^2) = Epump/vol - IR

and

I = Av

The Attempt at a Solution

My initial thought was that the current is the same. But then, since current is Av, I was second guessing myself that maybe the velocities are different. Any help's appreciated!

 

[asdf916]

Also, I'd appreciate it if you guys can help me on these

My guess was that the sewer gas is less than 1 ATM.

My guess is that the pressures are the same. Using the same energy density equation on the first post, I could eliminate the KE, Epump, and IR. That leaves the pressure and the PE. Since it's measuring the same height, the pressure's the same. Is this correct?

 

[m2003]

Your initial thought is correct - the current is the same. In this context, current refers to the flow of a fluid, such as water or air. The rate of flow, or current, is determined by the cross-sectional area of the pipe or channel (A) and the velocity of the fluid (v). Therefore, as long as the cross-sectional area remains constant, the current will also remain constant.

However, the velocity of the fluid can change depending on the presence of pumps. A pump is a device that increases the velocity of a fluid by adding energy to it. This increase in velocity results in an increase in the kinetic energy of the fluid, which can then be used for various purposes such as powering machinery or moving the fluid to a different location.

So, in summary, the current remains the same in a system, but the velocity of the fluid can change depending on the presence of pumps. The equations you provided are helpful in understanding the relationship between pressure, velocity, and energy in a fluid system, but they may not be directly applicable to every situation. It is important to consider the specific parameters and conditions of the system in question when analyzing the effects of pumps on fluid flow.