Conditions for a density matrix; constructing a density matrix

AI Thread Summary
The discussion focuses on the conditions necessary for a matrix to represent a density operator of a pure state. Key requirements include that the matrix must be Hermitian and have a trace equal to one. Participants explore the implications of these conditions, noting that specific elements of the matrix can be zero while others must sum to one. They also discuss the limitations of changing the basis to further restrict the matrix's form. Ultimately, the goal is to derive a general form for the density matrix under these constraints.
Juqon
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Homework Statement


What are the conditions so that the matrix \hat{p} describes the density operator of a pure state?


Homework Equations


[PLAIN]http://img846.imageshack.us/img846/2835/densitymatrix.png
p=\sum p_{j}|\psi_{j}><\psi_{j}

The Attempt at a Solution


I know that tr(\rho)=1 for pure states.
But I do not know how to construct the density matrix. Or is it \hat{p} already?
In my book, there is the example "hermitian, tr=1, [PLAIN]http://img89.imageshack.us/img89/4346/densitymatrixexample.png", but I do not know how they constructed that.

Maybe I can just say a+d+e=1; c,b arbitrary?
 
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What do you think about that?

[PLAIN]http://img155.imageshack.us/img155/7663/densitymatrixexamplep2.png
a²+bc=a (a\neq0) => a+\frac{bc}{a}=1
ab+bd=b (b\neq0) => a+d=1 <=> a= 1-d <=> d=1-a
ca+dc=c (c\neq0) => a+d = 1
cb+d²=2 (d\neq0) => d+\frac{cb}{d}=1
e=e²

a=0 v a= 1 - d
b € |R
c € |R
d=0 v d= 1 - a
e=0 v 1
 
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Ok, thanks, I have read that.

with the condition for the trace:
a+d+e=1 => e=0: a+d=1;
e=1: a=d=0

and since the matrix is hermitian and p^T=p:
b = c, c € |R

On the page you linked to it says only one element on the diagonale can be different from zero when you chose the right basis, but I think I can not change the basis here. So I think I can not further restrict it from that.
Right?
 
Juqon said:
Ok, thanks, I have read that.

with the condition for the trace:
a+d+e=1 => e=0: a+d=1;
e=1: a=d=0
For e=1, you can say a+d=0, which isn't quite the same as saying a=d=0.
and since the matrix is hermitian and p^T=p:
b = c, c € |R
Both b and c can be complex. At best you can say c=b*.
On the page you linked to it says only one element on the diagonale can be different from zero when you chose the right basis, but I think I can not change the basis here. So I think I can not further restrict it from that.
Right?
Yes, I agree. I think the problem wants you to find a general form for the density matrix.
 
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