Conducting sphere with chrage in centre

AI Thread Summary
A conducting sphere with a central cavity contains a point charge, leading to the induction of negative charge on the inner surface of the cavity. The electric field inside the cavity is influenced by the point charge, while the region between the cavity and the outer surface of the sphere has an electric field of zero. The electric field outside the sphere is determined by the total charge, which remains neutral overall. To accurately calculate the electric field, Gauss's Law must be applied rather than relying solely on logical assumptions. Therefore, a mathematical approach is necessary to find the electric field values in both the cavity and outside the sphere.
Taylor_1989
Messages
400
Reaction score
14

Homework Statement


Consider a conducting sphere of radius ##R_1##. Inside it there is a cavity, spherical in shape, with it origin at the same point as the conducting sphere and of radius ##R_2## ##(R_1>R_2)##. Assume there is a point charge equal to ##+Q## at the origin.

Use Gauss law to calculate the value of the electric field, E

Homework Equations

The Attempt at a Solution



I have no working because I am looking at this from a logical perspective and just want to know if my logic is correct.

my assumption is that this sphere with cavity is electrical neutral, so with the charge in the center being positive, then this will induce negative charge onto the inner shell, so then the electric field on the outside the shell will be the same, as the electric field insie the cavity and the, region between the outter surface and the cavity will be 0

Is this logic correct
 
Last edited:
Physics news on Phys.org
Taylor_1989 said:
... then the electric field on the outside the shell will be the same, as the electric field insie the cavity ...
Mostly correct except that the field inside the cavity has the same radial dependence as the field outside the sphere but it cannot be construed to be same.

Now what? You are asked to find the electric field using Gauss's Law. Logic alone will not do that.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top