Conduction Through Alum. Plate

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The discussion revolves around calculating heat transfer through a 0.100" aluminum plate in a setup involving an electric heat mat. The heat mat outputs 150 watts, translating to approximately 511.5 BTU/hr, which is crucial for determining its effectiveness in heating a motorcycle stored on an insulated subfloor. The user expresses confusion about the heat transfer calculations and whether concepts like lumped capacitance apply to their scenario. They seek clarification on how to accurately assess the heat transfer through the aluminum plate to ensure the heating system meets their needs. Understanding these calculations is essential for optimizing the heating performance in the garage setup.
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I am an ME with my years of heat transfer approx. 20 years back. I have a 3' x 7' insulated sub floor that utilizes an electric heat mat (2' x 5'). The heat mat is on top of the sub floor. Oh and a reflective layer between the heat mat and the sub floor. Finally I have a .100" diamond plate on top.
My heat mat puts out 150 watts, 1.3 amps, 96 ohms. Being the mat is 10 ft^2, that is 15 watts ft^2 which transfers to 400.92 btu/hr. (I think).
This whole unit will store a motorcycle in a garage with a cover. So assume natural convection. I am stumbling and/or confused on the method to find the heat transfer I can expect through the .100" alum. plate to know if my mat is capable.
I know for the most part this is basic but do I need lumped capacitance etc? Any help is more than appreciated. Thank you so much!
 
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Ooops my apologies ... I based my BTU's off a 12 watt mat whereas the actual is 15w. So my BTU's should be 511.5 btu/hr!?
 
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