Confused about equating energies

[Bhumble]

I'm trying to understand an RF induced chemical vapor deposition process. Without getting into anything complicated I get of got hung up on how to equate energies.

So I'm imagining a parallel plate capacitor that has charged particles oscillating between the two plates (or thinking of a single particle to keep things simple).

For a particle to move a specific distance W = -F dx so then there must have been E = F dx available.

So what I really want to know is how voltage and frequency play a part.
I feel like I'm missing something by just assuming E = hf = F dx = qV
It makes sense to me that the voltage and force would be proportional but I feel like I'm missing something in the relationship with frequency (unless it's buried in Planck's constant and I'm not seeing it). The part that is confusing me is that it seems like the voltage of the system is irrelevant to total energy and I don't understand how that could be.

Also would it be reasonable to subtract activation energies for breaking bonds from the energy of the system and assume the remaining energy is expended via F dx?

I know I'm completely neglecting all the thermal and quantum characteristics of the system. I'm just not on that level at this point and trying to understand from where I can grasp first. I appreciate any comments or insight.

 

[Valerie Park]

The relationship between voltage, frequency and energy in this system depends on the specific application and the materials involved. Generally speaking, energy is stored in the electric field of the capacitor, and is related to the voltage applied across it. The frequency of the RF field will determine how fast the energy is transferred from the capacitor to the material being deposited, and the rate of energy transfer will depend on the material properties, such as its dielectric constant. The energy transferred to the material is then used to break bonds, resulting in the deposition of material. The activation energies associated with bond breaking will also play a role in determining the rate of deposition.