Confused about mole ratio being relative or absolute

AI Thread Summary
In chemical reactions, the coefficients in a balanced equation represent the molar ratios of the reactants and products, indicating their relative amounts rather than absolute quantities. For example, in the reaction 3A + 1B -> 2C, the coefficients suggest that for every 3 moles of A and 1 mole of B, 2 moles of C are produced. This means that the ratios can be applied to any amount of the substances involved. When using a specific quantity, such as 0.8 moles of nitrogen in a reaction with a 2:1:3 ratio, the same ratios can be used to calculate the amounts of other reactants and products. Thus, consuming 0.8 moles of nitrogen would yield 0.4 moles of nitrogen and 1.2 moles of hydrogen based on the established ratios. Molar ratios are flexible and can be applied to any scale of measurement.
Dorslek
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Let's start with a generalized example:

3A + 1B -> 2C

For the mole amount next to each molecule, am I always to consider these as relative to one another or absolute? Most of the videos I have seen are describing the above as "for every 3 moles of A and 1 mole of B you get 2 moles of C". I believed at some point that these numbers were absolute however, after reading up on equilibrium I discovered that I was incorrect.

So for a reaction such as this:

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I have a ratio of 2:1:3. If I used up 0.8 moles of the nitrogen, I read that I would use the ratio to discover that I would produce 0.4 moles of nitrogen and 1.2 moles of hydrogen. Would anyone care to explain this to me?
 
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Dorslek said:
If I used up 0.8 moles of the nitrogen, I read that I would use the ratio to discover that I would produce 0.4 moles of nitrogen and 1.2 moles of hydrogen.

Correct. A molar ratio is just that, a ratio. It's a ratio in the same way that 1:2 is the same as 0.5:1 or 2:4. Just because the reaction says 2NH3 doesn't mean you have to use 2 moles.
 
.8NH3 x 1N2/2NH3= .4N2
.8NH3 x 3H2/2NH3= 1.2H2
 
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