Confused about Power Spectral Density (and relation with rms noise voltage)

AI Thread Summary
The discussion centers on the relationship between power spectral density and rms noise voltage in resistors, particularly in the context of thermal noise. The expression for noise power indicates that it is linked to the resistor's thermal characteristics and the selected frequency range, Δf. The rms noise voltage, V_rms, is dependent on both the resistance and the bandwidth, meaning that a larger frequency interval can result in greater noise disturbances. Δf represents the bandwidth of the system, which can vary based on the specific noise source or signal of interest. Understanding this relationship is crucial for accurately interpreting noise in broadband measurements and its implications for electrical systems.
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Hello,

In the chapter on thermal noise it says that the spectral distribution per Ohm of resistance is a certain shape (constant till a certain f and then ~ 1/f²).

This means that, in the frequency range below the cutoff value, the noise power in the bandwidth \Delta f is equal to 4k_B T \Delta f per Ohm of resistance.

What is this expression? Is it physically the power dissipitating in the resistor, at least a certain part of it corresponding to a specific selection of frequencies in the Fourier transform? So if you'd integrate over all the frequencies, you'd have the power dissipitated by the current in a resistor? Isn't this usually I or V-dependent? Or is this is a different phenomenon additional to the Joule heating?

The next sentence I find the most puzzling:
The root mean square (rms) noise voltage on a resistor R will then be equal to V_{rms} = \sqrt{4k_B T (\Delta f )R}. It can give large disturbances in broadband measurements.

So the rms voltage is a measure for the noise on the regular intended voltage, correct? But how is this dependent on a frequency-interval? What does it mean to say that if my interval of frequencies is bigger, the noise on my voltage is larger? I don't understand what interval of frequencies we're talking about. I would think it would only make sense if we integrated it over all the frequencies, then I would think the rms voltage would stand for the mean noise on the voltage, but what does it mean for a selected range of frequencies? What is a "broadband measurement"? Basically: what's the physical relevance of \Delta f? For example, the next line is "At 300K on 1 megaOhm resistor and Delta f = 10 MHz [...]" I get what it means to say "300K" and "1 megaOhm resistor", but not what "Delta f = 10 MHz" means...
 
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Delta f is simply the bandwidth of your system. Every electrical system has a finite bandwidth, and the rms voltage generated across the resistor depends on that.

Note that this also works with e.g. a bandpass filter. One way to generate white(=thermal) noise in certain bandwidth is to simply put a bandpas filter after the resistor.
 
Hm, so could I say that the quoted expression for the rms voltage in the OP (the one with Delta f) is actually integrated over all f, because the frequencies outside of the interval Delta f correspond to a zero amplitude in the signal?

And when you say "Delta f is simply the bandwidth of your system.", would it be just as okay to say "Delta f is simply the bandwidth of your signal", or is there an important difference?

Thank you
 
Delta f isn't always the bandwidth of the system. It may be wider or narrower than the system's bandwidth. It frequently depends on what you are doing or interested in. The delta f may be selected to concentrate on a particular noise signal or source, or to examine what is happening at a particular harmony of the primary signal function. It is not uncommon to only be concerned with part of the total system bandwidth, you maybe looking for the noise power or Vrms within that portion of the bandwidth.
 
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