Confusion on applying right hand rule

Click For Summary

Homework Help Overview

The discussion revolves around the application of the right-hand rule in the context of magnetic fields and forces acting on charged particles, specifically a proton moving in a uniform magnetic field.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the right-hand rule to determine the magnetic force on a proton but encounters discrepancies between their result and the textbook answer. They express confusion regarding the direction of the force and the application of the cross product.
  • Some participants question the conventions used for directional axes and suggest that the original poster may have mixed up the relationships between geographic directions (north/south, east/west) and the Cartesian coordinate system (x, y, z).
  • Others propose clarifying the representation of the magnetic field in vector form.

Discussion Status

The discussion is ongoing, with participants exploring the original poster's understanding of the right-hand rule and the conventions for directional axes. There is a focus on clarifying assumptions and ensuring that the relationships between the vectors are correctly established.

Contextual Notes

Participants note potential confusion stemming from the original poster's interpretation of geographic directions in relation to the Cartesian coordinate system, which may affect their application of the right-hand rule.

Genericcoder
Messages
130
Reaction score
0
Hi guys I always get confused when I do the right hand rule like here when I apply it to this problem I am getting different answer than what the book have.

A uniform magnetic field B, with magnitude 1.2 mT, points vertically upward throughout the volume of the room in which you are sitting. A proton with kinetic energy of 5.3 MeV moves horizontally to the north through a certain point in the room. What magnetic deflecting force acts on the proton as it passes through this point ? The proton mass is 1.67 * 10^-27 kg.

so Fb = 6.1 * 10^-15 N; the book then says the force is sideways in horzontally to the east. I am getting it pointing in the z direction even when using cross product

FB = q<v,0,0> x <0,B,0>

Fb = qvB k^ direction
 
Physics news on Phys.org
What's your convention for relating north/south, east/west, and up/down to the x, y, and z axes? You know you've mixed something up if the force isn't perpendicular to the B field and the velocity.

(I'm assuming that you are using i,, j, and k as unit vectors in the x, y, and z directions respectively).
 
Ye I am using i j k as unit vectros x,y,and z directions respectively.. but I think that's what I have not relating north/south up down to x and y and z directions..
 
Shouldn't your field be (0,0,B)?
 

Similar threads

Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
2K