shaner-baner
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Here is a fun problem, it's hard to write out clearly, but I'll try to do it w/ little confusion.
Is it, or is it not true that
(2^2^...^2)(n times)=(2^2^...^2)(n-1 times) mod n
so for example, when n=2, 2^2=2 ->
4=2 mod 2.
Is it, or is it not true that
(2^2^...^2)(n times)=(2^2^...^2)(n-1 times) mod n
so for example, when n=2, 2^2=2 ->
4=2 mod 2.