Conics Equation and Circle Problem: Solving for Unknown Variables

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Homework Statement



The equation ##x^2y^2-2xy^2-3y^2-4x^2y+8xy+12y=0## represents??

Homework Equations



circle: ##x^2 +y^2 = a^2##

The Attempt at a Solution


i know this has something to do with seperating out the variables but i don't seem to get the req equation
 
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Hysteria X said:

Homework Statement



The equation ##x^2y^@-2xy-3y^2-4x^2y+8xy+12y=0## represents??

Homework Equations



circle: ##x^2 +y^2 = a^2##

The Attempt at a Solution


i know this has something to do with seperating out the variables but i don't seem to get the req equation

Show us what you've tried.
 
You want to try to factor it somehow. Why are there two xy terms in your expression? Check for typos.
 
Mark44 said:
Show us what you've tried.
i divided the whole term by y^2 and i separated the y and x terms on both sides of the equation then i think the next step would be to convert into factors but how am i supposed to do that why y would be in the denominator in rhs??
 
Dick said:
You want to try to factor it somehow. Why are there two xy terms in your expression? Check for typos.

sorry its ##xy^2##
 
Hysteria X said:
sorry its ##xy^2##

Ok, then start trying to factor it. You can pull a y out right away.
 
Dick said:
Ok, then start trying to factor it. You can pull a y out right away.

##x^2y^2−2xy^2−3y^2−4x^2y+8xy+12y=0##
##y^2(x^2-2x-3)-4y(x^2-2x-3)=0##
##y-4=0##
##y=4##? what conic is that? is it a straight line :confused:
 
Hysteria X said:
##x^2y^2−2xy^2−3y^2−4x^2y+8xy+12y=0##
##y^2(x^2-2x-3)-4y(x^2-2x-3)=0##
##y-4=0##
##y=4##? what conic is that? is it a straight line :confused:

Yes, it's a line. It can happen. xy=1 is a hyperbola. xy=0 is two lines. That's a 'degenerate conic'. But actually since your equation is 4th degree, there's not necessarily any reason to expect it to be a conic. But y=4 isn't the whole story.
 
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Hysteria X said:
##x^2y^2−2xy^2−3y^2−4x^2y+8xy+12y=0##
##y^2(x^2-2x-3)-4y(x^2-2x-3)=0##
You skipped some steps here. Write the equation above as a product instead of a difference. In the two terms above there is a common factor: x2 - 2x - 3.
Hysteria X said:
##y-4=0##
##y=4##? what conic is that? is it a straight line :confused:
 
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