Connecting a conductor with a voltage source

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Doubling the distance between capacitor plates while adding a 100 V voltage source does not change the voltage between the plates, which remains at 200 V. This is because the voltage source compensates for the work done in separating the plates. A current is generated, and the additional voltage from the source performs the necessary work to maintain the voltage level. Understanding this concept is crucial in physics problems involving conductors and capacitors. The relationship between distance, voltage, and current is key to grasping how capacitors function in circuits.
fawk3s
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This kind of confuses me. You have a capacitor which has a voltage of 200 volts. Now when doubling the distance between the plates and adding a 100 V voltage source to it, it is said that the voltage between the capacitor plates stays the same, as in 200 V.
I don't follow. Someone care to explain?

Thanks in advance,
fawk3s
 
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fawk3s said:
This kind of confuses me. You have a capacitor which has a voltage of 200 volts. Now when doubling the distance between the plates and adding a 100 V voltage source to it, it is said that the voltage between the capacitor plates stays the same, as in 200 V.
I don't follow. Someone care to explain?

Thanks in advance,
fawk3s
Where is it said such a thing?
 
It was in a physics problem concerning conductors. But I just found out that its because the voltage source works against the work done when moving the plates. A current is created and the extra voltage created does the work. So the voltage between the plates should stay the same to a certain point.
 
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