Conservation of Energy: Proving the Relation ((mdx^2)/(dt^2))=F(x)

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The discussion outlines a proof of the conservation of energy using the relation ((mdx^2)/(dt^2))=F(x). It begins by defining kinetic energy K(x) as K(x) = 1/2 mv(x)^2 and work done W_{a → b} as the integral of force over a distance. The proof demonstrates that the work done equals the change in kinetic energy, W_{a → b} = K(b) - K(a). It then introduces potential energy U(x) as the negative integral of force and shows that the difference in potential energy equals the negative work done. Finally, it defines the total energy E of the system as E(x) = K(x) + U(x) and concludes that E remains constant, confirming the principle of conservation of energy.
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A) Given ((mdx^2)/(dt^2))=F(x)
prove conservation of energy
 
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Bonjour mon amie. Vous êtes belle aujourd'hui.

Here's how roughly: Define K(x) as K(x) = \frac{1}{2}mv(x)^2. Define W_{a \rightarrow b} as \int_a^b F(x')dx'. Show that W_{a \rightarrow b} = K(b) - K(a). Then define U(x) as -\int_s^x F(x')dx' where s is a fixed arbitrary point, and show that U(b) - U(a) = -W_{a \rightarrow b}. Then define the energy E of the system as E(x) = K(x) + U(x). Show how the previously found result imply that E is a constant.
 
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