Constant acceleration of hockey puck

AI Thread Summary
A hockey puck sliding on a frozen lake comes to rest after traveling 249 m with an initial velocity of 4.5 m/s. To find the constant acceleration, the equation v² = u² + 2ad is used, where v is the final velocity (0 m/s) and u is the initial velocity (4.5 m/s). By substituting these values, the calculation shows that the acceleration is approximately 0.0407 m/s². The discussion emphasizes the importance of using the correct equations that incorporate initial and final velocities along with displacement. This approach effectively resolves the problem of finding acceleration.
anna_chem
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Homework Statement


A hockey puck sliding on a frozen lake comes to rest after traveling 249 m. If its initial velocity is 4.5 m/s, what is its acceleration if that acceleration is assumed constant?


Homework Equations


V(t)= v(initial) + at
d= v(initial)*t + .5at^2

The Attempt at a Solution


V(t)= 4.5 m/s + at or 249 m= 4.5 m/s*t + at^2

I'm confused as to where to go from here. How can I go about finding t, so that I can find a? Or am I trying to go about it wrong?
 
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anna_chem said:

Homework Statement


A hockey puck sliding on a frozen lake comes to rest after traveling 249 m. If its initial velocity is 4.5 m/s, what is its acceleration if that acceleration is assumed constant?


Homework Equations


V(t)= v(initial) + at
d= v(initial)*t + .5at^2

The Attempt at a Solution


V(t)= 4.5 m/s + at or 249 m= 4.5 m/s*t + at^2

I'm confused as to where to go from here. How can I go about finding t, so that I can find a? Or am I trying to go about it wrong?

Yes, that is one way, but you are missing time, so that equation can't be used.
We need an equation with initial,final velocity,displacement and acceleration

like this one

v2=u2+2ad
 
Thanks for the quick response. So, given that initial velocity is 4.5 m/s and final velocity is 0, then:
4.5^2=0+498a thus a=.0407 m/s^2
Does that look correct?
 
anna_chem said:
Thanks for the quick response. So, given that initial velocity is 4.5 m/s and final velocity is 0, then:
4.5^2=0+498a thus a=.0407 m/s^2
Does that look correct?

v2=u2+2ad

v=final velocity

u=initial velocity.
 
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