Hi,(adsbygoogle = window.adsbygoogle || []).push({});

Let us assume that Hubble's Constant H is really constant. Therefore:

a' / a = H

where a is the scale factor.

The solution to this equation is:

a(t) = exp(H t)

This equation describes an accelerating universe with deceleration parameter q given by:

q = - a'' a / a'^2 = -1

This value of q is in agreement with current observations.

By the way, a constant value of H implies the Hubble radius which is a measure of the size of the observable Universe, R = c / H, is constant. If the above equation is true then in some sense the Universe is now static.

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Constant Hubble parameter -> accelerating Universe?

Loading...

Similar Threads for Constant Hubble parameter |
---|

I Asymptotic Hubble constant |

A Dark energy = cosmological constant, any problems with that? |

I Where are the Constants of Nature stored in Multiverse? |

I Deriving the Cosmological Constant |

B Hubble's constant and Minkowski spacetime |

**Physics Forums - The Fusion of Science and Community**