- #1
johne1618
- 371
- 0
Hi,
Let us assume that Hubble's Constant H is really constant. Therefore:
a' / a = H
where a is the scale factor.
The solution to this equation is:
a(t) = exp(H t)
This equation describes an accelerating universe with deceleration parameter q given by:
q = - a'' a / a'^2 = -1
This value of q is in agreement with current observations.
By the way, a constant value of H implies the Hubble radius which is a measure of the size of the observable Universe, R = c / H, is constant. If the above equation is true then in some sense the Universe is now static.
Let us assume that Hubble's Constant H is really constant. Therefore:
a' / a = H
where a is the scale factor.
The solution to this equation is:
a(t) = exp(H t)
This equation describes an accelerating universe with deceleration parameter q given by:
q = - a'' a / a'^2 = -1
This value of q is in agreement with current observations.
By the way, a constant value of H implies the Hubble radius which is a measure of the size of the observable Universe, R = c / H, is constant. If the above equation is true then in some sense the Universe is now static.