Constructing a bijection between [0,1]^2 and [0,1] using decimal representation.

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Hi everyone, I've had some troubles to solve some exercices of real analysis.1. Prove that card( \mathbb{R}^{\mathbb{N}}) = card(\mathbb{R}).

In this one I have considered that card(0,1)= card(\mathbb{R}) and tried to construct a bijection f: (0,1)\rightarrow \mathbb{R}^{\mathbb{N}}.2. Construct a bijection between [0,1]^{2} and \mathbb{R}

-Thanks.
 
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Hurin said:
Hi everyone, I've had some troubles to solve some exercices of real analysis.


1. Prove that card( \mathbb{R}^{\mathbb{N}}) = card(\mathbb{R}).

In this one I have considered that card(0,1)= card(\mathbb{R}) and tried to construct a bijection f: (0,1)\rightarrow \mathbb{R}^{\mathbb{N}}.

Try to use that

\mathbb{R}=2^\mathbb{N}

and hence

\mathbb{R}^\mathbb{N}=2^{\mathbb{N}\times \mathbb{N}}

2. Construct a bijection between [0,1]^{2} and \mathbb{R}

It might be easy to first construct a bijection between [0,1]^2 and [0,1]. Try to do something with the decimal representation here. Given

0.x_1x_2x_3...~\text{and}~0.y_1y_2y_3...

how could you combine these two numbers??
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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