Constructive Interference in Coherent Antenna Arrays

AI Thread Summary
The discussion centers on a radio transmitting station with two coherent antennas, focusing on the concepts of wavelength and constructive interference. The wavelength of the electromagnetic wave is calculated to be 3 meters using the formula λ = c/f, where c is the speed of light. The path difference (PD) at point P is expressed as PD = 10 - 2x, and constructive interference occurs when PD equals mλ, leading to specific values of x for interference points. Participants clarify that for electromagnetic waves, the speed of light should be used, not the speed of sound, and identify an algebraic error in the calculation of x for constructive interference. Overall, the conversation emphasizes the importance of correct calculations and understanding the principles of wave interference.
not_a_physics_major
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Homework Statement
A radio transmitting station operating at a frequency f=100 MHz has two identical antennas that radiate in phase (in other words, coherent with respect to each other). Antenna B is 10 m to the right of antenna A. Consider the point P between the antennas, and along the line connecting them a horizontal distance x to the right of antenna A.

a) What is the wavelength of the electromagnetic wave?
b) At point P, what is the path difference (PD) between the waves coming from the two antennas (give your answer in terms of x)?
c) For what values of x will constructive interference occur at point P?
d) How many constructive interference points will be there on the line between the two antennas?

Relevant Equations
c=λf
v=λf?

The attempt at a solution
a.) c=λf, so λ=(3*108m/s)/(1*108Hz)=3m. This gave me the correct answer according to the study guide, but I've seen some people use v (speed of sound) instead of c (speed of light). I'm not sure which is correct.
b.) PD= (10-x)-x= 10-2x
c.) Constructive interference occurs when PD= mλ. So, x=-(mλ)/20. For m values 1-4, x= -0.15, 0.3, 0.45, 0.6 According to the answer key this is wrong, but I don't understand how to get the right answer.
d.) The total distance is 10m, so I would keep plugging in m values until I get an x ≥10.
 
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not_a_physics_major said:
...
a.) c=λf, so λ=(3*108m/s)/(1*108Hz)=3m. This gave me the correct answer according to the study guide, but I've seen some people use v (speed of sound) instead of c (speed of light). I'm not sure which is correct. Do radio waves travel at the speed of light or at the speed of sound?
b.) PD= (10-x)-x= 10-2x Yes
c.) Constructive interference occurs when PD= mλ. So, x=-(mλ)/20. For m values 1-4, x= -0.15, 0.3, 0.45, 0.6 According to the answer key this is wrong, but I don't understand how to get the right answer. If PD=mλ. and PD=10 -2x then mλ.=10 -2x which does not rearrange to your expression
d.) The total distance is 10m, so I would keep plugging in m values until I get an x ≥10.
 
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not_a_physics_major said:
Homework Statement
A radio transmitting station operating at a frequency f=100 MHz has two identical antennas that radiate in phase (in other words, coherent with respect to each other). Antenna B is 10 m to the right of antenna A. Consider the point P between the antennas, and along the line connecting them a horizontal distance x to the right of antenna A.

a) What is the wavelength of the electromagnetic wave?
b) At point P, what is the path difference (PD) between the waves coming from the two antennas (give your answer in terms of x)?
c) For what values of x will constructive interference occur at point P?
d) How many constructive interference points will be there on the line between the two antennas?

Relevant Equations
c=λf
v=λf?

The attempt at a solution
a.) c=λf, so λ=(3*108m/s)/(1*108Hz)=3m. This gave me the correct answer according to the study guide, but I've seen some people use v (speed of sound) instead of c (speed of light). I'm not sure which is correct.
b.) PD= (10-x)-x= 10-2x
c.) Constructive interference occurs when PD= mλ. So, x=-(mλ)/20. For m values 1-4, x= -0.15, 0.3, 0.45, 0.6 According to the answer key this is wrong, but I don't understand how to get the right answer.
d.) The total distance is 10m, so I would keep plugging in m values until I get an x ≥10.
Welcome to the PF.:smile:

For EM waves, use the velocity c. For sound waves, use the speed of sound for the velocity. Makes sense?

And you get constructive interference when the path length difference is a multiple of 2π, not just π. You can see that by looking at the plot of a sinusoidal waveform. See how the wave repeats itself every 2π? If you add two waves that are π apart in phase, they cancel each other out. Can you see that now? :smile:

ADD -- Sorry, I mistread your post. You did say when the PD is a multiple of the wavelength, not of π.

https://betterexplained.com/wp-content/uploads/sine/sine-plot.gif
sine-plot.gif


EDIT -- Merlin types faster than I do! :smile:
 

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not_a_physics_major said:
b.) PD= (10-x)-x= 10-2x
c.) Constructive interference occurs when PD= mλ. So, x=-(mλ)/20.
The calculation for x went wrong. If you start from mλ = 10 - 2x, you don't get x = -(mλ)/20.
 
Chandra Prayaga said:
The calculation for x went wrong. If you start from mλ = 10 - 2x, you don't get x = -(mλ)/20.
Thank you! I suspected there was an algebra error somewhere!
 
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berkeman said:
Welcome to the PF.:smile:

For EM waves, use the velocity c. For sound waves, use the speed of sound for the velocity. Makes sense?

And you get constructive interference when the path length difference is a multiple of 2π, not just π. You can see that by looking at the plot of a sinusoidal waveform. See how the wave repeats itself every 2π? If you add two waves that are π apart in phase, they cancel each other out. Can you see that now? :smile:

ADD -- Sorry, I mistread your post. You did say when the PD is a multiple of the wavelength, not of π.

https://betterexplained.com/wp-content/uploads/sine/sine-plot.gif
View attachment 216958

EDIT -- Merlin types faster than I do! :smile:
Thank you for both the welcome and the explanation!
 
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Thank you very much! :D
 
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