Continuity and intermediate value theorem

saquibaa
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let [x,y] be in R and be a closed bounded interval and let g: [x,y] --> R be a function. suppose g is continuous. let k exist in R. suppose that k is strictly between g(x) and g(y) and that g-1(k) has at least 2 elements. prove that there is some m that is strictly between g(x) and g(y) and that g-1(m) has at least three elements.

i can't visualize this (i.e. with just 2 elements for g-1(k)). i know i need to use intermediate value theorem but can't come up with anything concrete.
 
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i can't visualize this (i.e. with just 2 elements for g-1(k))

Start by drawing a picture. Pick where g(x) and g(y) are, and pick two points that have the same y-value in between x and y. Then start drawing a couple of graphs
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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