Density of Countable Sets in ℝ and its Implications for Continuous Functions

SMA_01
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Let f and g be two continuous functions on ℝ with the usual metric and let S\subsetℝ be countable. Show that if f(x)=g(x) for all x in Sc (the complement of S), then f(x)=g(x) for all x in ℝ.

I'm having trouble understanding how to approach this problem, can anyone give me a hint leading me in the right direction?

Thank you.
 
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SMA_01 said:
Let f and g be two continuous functions on ℝ with the usual metric and let S\subsetℝ be countable. Show that if f(x)=g(x) for all x in Sc (the complement of S), then f(x)=g(x) for all x in ℝ.

I'm having trouble understanding how to approach this problem, can anyone give me a hint leading me in the right direction?

Thank you.

How about trying to show that Sc is dense in R? That would do it, yes?
 
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Dick said:
How about trying to show that Sc is dense in R? That would do it, yes?

I was told that Sc is dense because S is countable. I'm not sure if that's a theorem, but should I just prove density using the definition or is there a simpler way?
 
SMA_01 said:
I was told that Sc is dense because S is countable. I'm not sure if that's a theorem, but should I just prove density using the definition or is there a simpler way?

Use the definition. You'll have to add to that what you hopefully know about some subsets of R being uncountable.
 
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