Contraction Mapping Theorem Question

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Homework Help Overview

The discussion revolves around the Contraction Mapping Theorem (CMT) and its application to the function g defined on the interval [0,∞) by g(x) = x + e^(-2x). Participants are examining whether g qualifies as a contraction mapping based on the provided inequality |g(x2) − g(x1)| < |x2 − x1| for distinct x1 and x2 in the domain.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the definition of a contraction mapping and questioning the necessity of finding a constant c < 1 to satisfy the contraction condition. There is also a discussion about the clarity of the CMT and its implications for the problem at hand.

Discussion Status

Some participants have provided insights into the requirements for g to be considered a contraction, emphasizing the need for a specific constant c. Others are seeking clarification on the definitions and implications of the CMT, indicating a productive exploration of the topic.

Contextual Notes

There are mentions of potential confusion regarding the notation in the function definition and the interpretation of the CMT, which may affect participants' understanding of the problem.

nugget
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Homework Statement



Consider the function g : [0,∞) → R defined by g(x) = x + e−2x.

Given |g(x2) − g(x1)| < |x2 − x1| for all x1, x2 ∈ [0,∞) with x1 ≠ x2.

Is g a contraction on [0,∞)? Why?

Homework Equations



I think we are intended to use the given equation and the CMT

CMT states that |f(x)-f(y)|=c|x-y|, where x,y∈R.

Which is similar to |g(x2) − g(x1)|<|x2 − x1|

The Attempt at a Solution



I really don't know where to begin with this; I'm not simply after the answer though, just a prod in the right direction would be great
 
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On my computer, the formula for g(x) displays an unreadable symbol before the e-2x. Also, I confess that I have only seen CMT from browsing my friend's analysis book, and it doesn't exactly say
CMT states that |f(x)-f(y)|=c|x-y|, where x,y∈R.
.
Are they equivalent?

EDIT: The actual statement I read is at http://en.wikipedia.org/wiki/Banach_fixed_point_theorem
 
Last edited:
g is a contraction precisely when there is some positive real number c < 1 with

[tex]|g(y) - g(x)| < c |y-x|[/tex]

for all x,y in the domain.

You have to either find a positive c < 1 that satisfies the inequality above for all [tex]x,y \in [0,\infty)[/tex] or show no positive c < 1 exists which satisfies the inequality. Note that

[tex]|g(y) - g(x)| < |y-x|[/tex]

does not show g is a contraction. The constant 0 < c < 1 really is needed (check the proof of the contraction mapping theorem to see why if you're interested; it's a really cool piece of mathematics).
 
Last edited:
nugget said:

Homework Statement



Consider the function g : [0,∞) → R defined by g(x) = x + e−2x.

Given |g(x2) − g(x1)| < |x2 − x1| for all x1, x2 ∈ [0,∞) with x1 ≠ x2.

Is g a contraction on [0,∞)? Why?

Homework Equations



I think we are intended to use the given equation and the CMT

CMT states that |f(x)-f(y)|=c|x-y|, where x,y∈R.
No, it doesn't. That is simply the definition of "contraction map". The CMT states that if f is a contraction map that take set S into itself, then it has exactly one fixed point in S.

Which is similar to |g(x2) − g(x1)|<|x2 − x1|

The Attempt at a Solution



I really don't know where to begin with this; I'm not simply after the answer though, just a prod in the right direction would be great
 

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