Convergence of a double summation using diagonals

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Shawn Garsed
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Homework Statement


Show that ##\sum_{k=2}^\infty d_k## converges to ##\lim_{n\to\infty} s_{nn}##.

Homework Equations


I've included some relevant information below:

Ri4oy.jpg


The Attempt at a Solution


So far I've managed to show that ##\sum_{k=2}^\infty |d_k|## converges, but I don't know how to move on from there.

P.S.
I also posted this question to math.stackexchange but haven't gotten an answer there.
 

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I'm not really sure I understand what the question is?

note: I think your author is abusing language here. The array entries (at least using matrix terminology) are better described as anti-diagonals.

Suppose you have and ##m## x ##n## array. You can sum its entries any way you want: by row, by column, by diagonal or by anti-diagonal, or some more exotic approach -- it doesn't matter as long as you include every number once in your sum, and no numbers twice.

Why? We're dealing with scalars in ##\mathbb R## (and possibly ##\mathbb C##) here, and scalar addition commutes in ##\mathbb R##. It could be instructive to write out the indexing of the sums for these 4 different cases.

Some care is needed when ##\infty## is involved, but you've passed the absolute convergence test based on line 2 of your picture. With absolute convergence out of the way

So the question is either just about indexing or commutativity of addition in reals? Or something else?
 
yikes. I didn't read this carefully enough.

To the extent everything is real non-negative (and not identically zero which is easy to handle) the convergent sum in line 2 is #S \gt 0##, and we can renormalize / assume without loss of generality that it sums to one. Since the anti-diagonal summing is just a re-partitioning argument (union of disjoint sets) it would seem to motivate countable additivity axiom in probability. But I don't think this is what the problem is looking for, nor is it restricted to non-negative reals.