Convergence of Integral with Divergent Function at 0+

Aki
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I want to know if the integral

\int_0^{\infty} dx/(4x^3 + x^(1/3))

is convergent or divergent?Thanks
 
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What have you tried? Have you compared it with integrals whose convergece/divergence you know? Keep in mind your integrand is also undefined at 0.

Use {} instead of () to group things in latex, click on \int_{0}^{\infty}
 
Well I'm just not sure what happens when

\int_{0}^{1}dx/x^{1/3}

I think it converges, but I"m not too sure.
because when that function is below 1/x on the graph
 
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What is the anti-derivative of \frac{1}{x^{\frac{1}{3}}}= x^{-\frac{1}{3}}
 
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Is the function \frac{1}{4x^{3}+x^{1/3}} ? If so, what is its limit to 0^{+} ?

Daniel.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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