Convergence or Divergence: Analyzing [(3^-n)+(n^-1)] Series from n=1 to inf

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Ok, so the problem is [(3^-n)+(n^-1)] and I have to determine if it converges are diverges. from n=1 to inf. The problem is that individually I know that the 3^-n should converge and that n^-1 should diverge. But I don't understand what happens when your taking the series of the two combines. I think it would diverge, because of the n^-1, but I don;t know what test to prove it or if I even have the right idea. If anyone has any suggestions of a test to do, I tried the root test but found it to be 1 which is inconclusive, and I don't know where to go with this problem.
 
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You know that 1/n diverges from the integral test, and that 3-n is only making the sum bigger, so it diverges.
 
Thank you so much. I just wasn't sure if you could do that.
 
To firm this up, if a_n = e^{-n} + n^{-1} and b_n = n^{-1}.
you can use the comparison test to show that \sum_{n=1}^\infty a_n diverges.
 
By the way, it would have been clearer if you had stated from the start that the question was whether or not the series e^{-n}+n^{-1} converges. Of course, the sequence obviously converges to 0 so everyone assumed you mean "series" but it was ambiguous which you meant.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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